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2 years ago

Find the distance between the centers of the circles (x-1)²+(y+2)²=16 and (x+2)²+(y+1)²=14.

Mathematics

1 answer:

Dovator [93]2 years ago

3 0

Answer: $D=\sqrt{10}$

Step-by-step explanation:

Given

circle

$\left ( x-1\right )^2+\left ( y+2\right )^2=16$

center of circle is (1,-2)

second circle

$\left ( x+2\right )^2+\left ( y+1\right )^2=14$

center of circle is (-2,-1)

Distance between two points

$D=\sqrt{\left ( y_2-y_1\right )^2+\left ( x_2-x_1\right )^2}$

$D=\sqrt{\left ( -2+1\right )^2+\left ( 1+2\right )^2}$

$D=\sqrt{10}$

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0.23x + 1.47 = 0.37x – 1.05

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0.23x+1.47=0.37x-1.05

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To find out how much each book cost first we will subract to find out how many 2 books cost. Then we will divide. last but not least we will check our wok. Lets do it:-

30 - 8.95 = <span>21.05
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CHECK OUR WORK:-

13.80 + 7.25 = 21.05
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We were RIGHT!!!

Now lets divide:-

13.80 ÷ 2 = 6.90
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CHECK OUR WORK:-

6.90 × 2 = 13.80
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