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raketka [301]
3 years ago
14

Solve for X in the given interval. sec x = -2sr3/3, for pi/2 less than or equal to x less than or equal to pi

Mathematics
1 answer:
notsponge [240]3 years ago
6 0

Answer:

B

Step-by-step explanation:

Using the trig. identity

cos x = \frac{1}{secx}

Given

secx = - \frac{2\sqrt{3} }{3} , then

cos x = - \frac{3}{2\sqrt{3} } × \frac{\sqrt{3} }{\sqrt{3} } = - \frac{3\sqrt{3} }{6} = - \frac{\sqrt{3} }{2} , thus

x = cos^{-1} (- \frac{\sqrt{3} }{2} ) = \frac{5\pi }{6} → B

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