3 years ago

Solve for X in the given interval. sec x = -2sr3/3, for pi/2 less than or equal to x less than or equal to pi

Mathematics

1 answer:

notsponge [240]3 years ago

6 0

Answer:

Step-by-step explanation:

Using the trig. identity

cos x = $\frac{1}{secx}$

Given

secx = - $\frac{2\sqrt{3} }{3}$ , then

cos x = - $\frac{3}{2\sqrt{3} }$ × $\frac{\sqrt{3} }{\sqrt{3} }$ = - $\frac{3\sqrt{3} }{6}$ = - $\frac{\sqrt{3} }{2}$ , thus

x = $cos^{-1}$ (- $\frac{\sqrt{3} }{2}$ ) = $\frac{5\pi }{6}$ → B

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DiKsa [7]

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mr_godi [17]

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3 years ago

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zvonat [6]

Answer:

Step-by-step explanation:

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