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Sloan [31]
3 years ago
14

Write the balanced net ionic equation for the reactions that occur when the given aqueous solutions are mixed. Include the physi

cal states. A. nitric acid, HNO 3 , and calcium hydroxide, Ca ( OH ) 2 net ionic equation: B. lead(II) nitrate, Pb ( NO 3 ) 2 , and potassium iodide, KI
Chemistry
1 answer:
Anestetic [448]3 years ago
7 0

Answer:

a. 2 H⁺ (aq) + 2 OH⁻ (aq) → 2H₂O(l)

b. Pb²⁺(aq) + 2I⁻(aq) → PbI₂(s)

Explanation:

First of all, we must determine if the reactants produce precipitates:

A. HNO₃, Ca(OH)₂

B. Pb(NO₃)₂, KI

A. This is a neutralization reaction:

Acid + Base → Water and Salt

The net ionic equation shows, that water is produced

We dissociate the compounds:

HNO₃  →  H⁺(aq)  +  NO₃⁻(aq)

Ca(OH)₂(aq) → Ca²⁺(aq) + 2OH⁻(aq)

Ionic complete equation:

2H⁺(aq) + 2NO₃⁻(aq)  +  Ca²⁺(aq) + 2OH⁻(aq) → Ca²⁺(aq) + 2NO₃⁻(aq) + H₂O(l)

Net ionic equation:   2 H⁺ (aq) + 2 OH⁻ (aq) → H₂O(l)

B. Pb(NO₃)₂, KI

We dissociate: Pb(NO₃)₂ (aq) →  Pb²⁺(aq) + 2NO₃⁻(aq)

KI(aq) →  K⁺(aq) + I⁻(aq)

Salts from nitrate are soluble but, when the iodide reacts, it can make a lead iodide precipitate

Ionic complete equation:

Pb²⁺(aq) + 2NO₃⁻(aq)  +  K⁺(aq) + 2I⁻(aq) → K⁺(aq) + 2NO₃⁻(aq) +PbI₂(s)

Net ionic equation: Pb²⁺(aq) + 2I⁻(aq) → PbI₂(s)

We cancel the repeated ions

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Pure iron, Fe , can be produced from an ore called hematite, Fe2O3 , by reaction with carbon at high temperatures. 2Fe2O3+3C⟶4Fe
Sophie [7]

70 tons of hematite (Fe₂O₃) is needed to produce 49 tons of iron (Fe).

We'll begin by calculating the tons of hematite (Fe₂O₃) that reacted and the tons of Fe produced from the balanced equation. This is illustrated below:

2Fe₂O₃ + 3C —> 4Fe + 3CO₂

Molar mass of Fe₂O₃ = (56×2) + (16×3) = 160 g/mol

Mass of Fe₂O₃ from the balanced equation = 2 × 160 = 320 g

Divide by 907185 to express in ton

320 / 907185 = 0.000353 ton

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Divide by 907185 to express in ton

224 / 907185 = 0.000247 ton

<h3>SUMMARY </h3>

From the balanced equation above,

0.000353 ton of Fe₂O₃ reacted to produce 0.000247 ton of Fe.

Finally, we shall determine the tons of hematite (Fe₂O₃) needed to produce 49 tons of Fe. This can be obtained as follow:

From the balanced equation above,

0.000353 ton of Fe₂O₃ reacted to produce 0.000247 ton of Fe.

Therefore,

X ton of Fe₂O₃ will react to produce 49 tons of Fe i.e

X ton of Fe₂O₃ = \frac{0.000353 * 49}{0.000247} \\\\

X ton of Fe₂O₃ = 70 tons

Thus, 70 tons of hematite (Fe₂O₃) is needed to produce 49 tons of Fe.

Learn more: brainly.com/question/15343472

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