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Sloan [31]
3 years ago
14

Write the balanced net ionic equation for the reactions that occur when the given aqueous solutions are mixed. Include the physi

cal states. A. nitric acid, HNO 3 , and calcium hydroxide, Ca ( OH ) 2 net ionic equation: B. lead(II) nitrate, Pb ( NO 3 ) 2 , and potassium iodide, KI
Chemistry
1 answer:
Anestetic [448]3 years ago
7 0

Answer:

a. 2 H⁺ (aq) + 2 OH⁻ (aq) → 2H₂O(l)

b. Pb²⁺(aq) + 2I⁻(aq) → PbI₂(s)

Explanation:

First of all, we must determine if the reactants produce precipitates:

A. HNO₃, Ca(OH)₂

B. Pb(NO₃)₂, KI

A. This is a neutralization reaction:

Acid + Base → Water and Salt

The net ionic equation shows, that water is produced

We dissociate the compounds:

HNO₃  →  H⁺(aq)  +  NO₃⁻(aq)

Ca(OH)₂(aq) → Ca²⁺(aq) + 2OH⁻(aq)

Ionic complete equation:

2H⁺(aq) + 2NO₃⁻(aq)  +  Ca²⁺(aq) + 2OH⁻(aq) → Ca²⁺(aq) + 2NO₃⁻(aq) + H₂O(l)

Net ionic equation:   2 H⁺ (aq) + 2 OH⁻ (aq) → H₂O(l)

B. Pb(NO₃)₂, KI

We dissociate: Pb(NO₃)₂ (aq) →  Pb²⁺(aq) + 2NO₃⁻(aq)

KI(aq) →  K⁺(aq) + I⁻(aq)

Salts from nitrate are soluble but, when the iodide reacts, it can make a lead iodide precipitate

Ionic complete equation:

Pb²⁺(aq) + 2NO₃⁻(aq)  +  K⁺(aq) + 2I⁻(aq) → K⁺(aq) + 2NO₃⁻(aq) +PbI₂(s)

Net ionic equation: Pb²⁺(aq) + 2I⁻(aq) → PbI₂(s)

We cancel the repeated ions

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A solution with a pH level of 7.0 would be considered as an Basic, Acidic, or neutral
ASHA 777 [7]

Answer:

Neutral.

Explanation:

A solution with 7 on the pH scale would be neutral.

4 0
3 years ago
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Hydrogen cab be obtained economically as a byproduct in the electrolysis of____________
yarga [219]
Water, because electrolysis is using electricity to break the bond of water to release 2 Hydrogens and the 1 Oxygen.
4 0
3 years ago
A large balloon is initially filled to a volume of 25.0 L at 353 K and a pressure of 2575 mm Hg. What volume of gas will the bal
bija089 [108]

Answer:

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

Explanation:

Using Ideal gas equation for same mole of gas as

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

Given ,  

V₁ = 25.0 L

V₂ = ?

P₁ = 2575 mm Hg

Also, P (atm) = P (mm Hg) / 760

P₁ = 2575 / 760 atm = 3.39 atm

P₂ = 1.35 atm

T₁ = 353 K

T₂ = 253 K

Using above equation as:

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

\frac{{3.39}\times {25.0}}{353}=\frac{{1.35}\times {V_2}}{253}

\frac{1.35V_2}{253}=\frac{3.39\times \:25}{353}

Solving for V₂ , we get:

<u>V₂ = 45.0 L</u>

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

4 0
4 years ago
5K + KNO3 ------ 3K2O + N
masya89 [10]

Answer:

174,957.143 grams of potassium and 89,228.478 grams of potassium nitrate will be needed.

Explanation:

5K +KNO_3\rightarrow 3K_2O + N

Mass of nitrogen =  27 lbs = 12,247 g

1 lbs = 453.592 g

Moles of nitrogen = \frac{12,247 g}{14 g/mol}=874.786 mol

According to reaction, 1 mole of nitrogen is produced from 5 moles of potassium and 1 mole of potassium nitrate.

Then 874.786 mol of nitrogen will be obtained from :

\frac{5}{1}\times 874.786 mol=4,373.928 mol of potassium.

Then 874.786 mol of nitrogen will be obtained from :

\frac{1}{1}\times 874.786 mol=874.789 mol of potassium nitrate.

Mass of 4,373.928 moles of potassium:

4,373.928 mol\times 40 g/mol=174,957.143 g of potassium

Mass of 874.789 moles of potassium nitrate:

874.789 mol\times 102 g/mol=89,228.478 g of potassium nitrate

3 0
3 years ago
Please hurry! And help!!
lyudmila [28]

Answer:

I guess the answer is compound

Explanation:

Coz compound it is on there playing with me again Go ahead and paste it in the class

4 0
3 years ago
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