Answer:
CH4 +2 O2 — CO2 +2 H2O
Now we see that for 1 mol i.e. 16 grams of methane results in 1 mol of CO2 or 44 grams of CO2.
That means for 3 moles of methane , we will obtain 3 moles of CO2 OR for 48 (3*16) grams of CO2 , we will obtain (44*3) 132 grams of CO2 .That's it….
Explanation:
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Answer:
B. 091
Explanation:
When we add these two equilbria, the equilibrium constant for the resultant equilibrium is the product of the first two.
Notice that when we add the first two reactions in this question, we obtain the equilibrium for which we are seeking its equilibrium constant. Therefore,
A(g) + B(g) ? AB(g) Kc₁ = [AB] / [A][B]
+
AB(g) + A(g) ? A2B(g) Kc₂ = [A₂B] /[ AB][A]
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2 A(g) + B(g) ⇄ A₂B(g) Kc₃ = [A₂B] / [A]²[B]
Kc₁Kc₂ = [AB] / [A][B] x [A₂B] / [AB][A] = [A₂B] / [A]²[B]
Thus,
Kc₃ = 0.24 x 3.8 = 0.91
This procedure is not limited to two reaction, it could done for more than two, as long as the desired equilibrium is the desired one.
<span> If mass remains the same while the volume of a substance increases and the density of the substance will decrease or, volume decreases and density increase, 'cause density equals mass divided in volume, which means that volume and density are inversely proporcional</span>
Answer:
Carbon
Explanation:
If we keep many type of gas with carbon It will be mixture of Gases