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Evgesh-ka [11]
3 years ago
13

Hello there!

Chemistry
1 answer:
Alenkasestr [34]3 years ago
4 0

Answer:

Mass of carbon dioxide = 7.48 g

Explanation:

Given data:

Mass of lithium carbonate = 12.5 g

Mass of carbon dioxide produced = ?

Solution:

Chemical equation:

Li₂CO₃  →  Li₂O + CO₂

Number of moles of Li₂CO₃:

Number of moles = mass/ molar mass

Number of moles = 12.5 g /73.89 g/mol

Number of moles = 0.17 mol

Now we will compare the moles of Li₂CO₃  with CO₂.

                   Li₂CO₃        :            CO₂

                     1                :               1

                  0.17             :             0.17

Mass of carbon dioxide:

Mass of carbon dioxide = number of moles × molar mass

Mass of carbon dioxide =   0.17 mol ×  44 g/mol

Mass of carbon dioxide = 7.48 g

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We'll begin by writing the balanced equation for the reaction. This illustrated below:

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<h3>How to determine the volume of NH₃ produced</h3>

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1 dm³ of N₂ reacted to produced 2 dm³ NH₃

Therefore,

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We'll begin by obtained the mole of 4.48 dm³ of NH₃. Details below:

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4.48 dm³ = 0.2 mole of NH₃

Finally, we shall determine the mass of NH₃ as follow:

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Learn more about stoichiometry:

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