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3 years ago

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Chemistry

1 answer:

Alenkasestr [34]3 years ago

4 0

Answer:

Mass of carbon dioxide = 7.48 g

Explanation:

Given data:

Mass of lithium carbonate = 12.5 g

Mass of carbon dioxide produced = ?

Solution:

Chemical equation:

Li₂CO₃ → Li₂O + CO₂

Number of moles of Li₂CO₃:

Number of moles = mass/ molar mass

Number of moles = 12.5 g /73.89 g/mol

Number of moles = 0.17 mol

Now we will compare the moles of Li₂CO₃ with CO₂.

Li₂CO₃ : CO₂

1 : 1

0.17 : 0.17

Mass of carbon dioxide:

Mass of carbon dioxide = number of moles × molar mass

Mass of carbon dioxide = 0.17 mol × 44 g/mol

Mass of carbon dioxide = 7.48 g

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Answer: Option (D) is the correct answer.

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3 years ago

1. Name three obstacles that Mendeleev faced in his life?

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Answer:

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2 years ago

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Sladkaya [172]

Answer :

(a) The moles of water produced are 145.35 moles.

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<u>Solution for part (b) : Given,</u>

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Now we have to calculate the moles of $O_2$

The balanced chemical reaction is,

$2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O$

From the balanced reaction we conclude that

As, 2 moles of $C_8H_{18}$ react with 25 moles of $O_2$

So, 7.702 moles of $C_8H_{18}$ react with $\frac{7.702}{2}\times 25=96.275$ moles of $O_2$

Now we have to calculate the mass of $O_2$ .

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3 years ago

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Answer:

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