Answer:
I belive it is the range hope it helped! :)
Explanation:
Answer:
the mirror is 12 cm away from the image
Explanation:
; the image will be virtual and it will form at 12 cm distance behind the mirror.
Answer:
339.2K
Explanation:
Using Charles law equation;
V1/T1 = V2/T2
Where;
V1 = initial volume (L)
V2 = final volume (L)
T1 = initial temperature (K)
T2 = final temperature (K)
According to the information provided in this question,
V1 = 2.97 L
V2 = 3.42 L
T1 = 21.6°C = 21.6 + 273 = 294.6K
T2 = ?
Using V1/T1 = V2/T2
2.97/294.6 = 3.42/T2
Cross multiply
2.97 × T2 = 294.6 × 3.42
2.97T2 = 1007.532
T2 = 1007.532 ÷ 2.97
T2 = 339.236
The final temperature is 339.2K
Answer:
6.48L
Explanation:
Given parameters:
V₁ = 2.5L
P₁ = 105 kPa
P₂ = 40.5 kPa
Condition: constant temperature
Unknown:
V₂ = ?
Solution:
To solve this problem, we are considering pressure and volume relationship. This should be solved by applying the knowledge of Boyle's law.
The law states that "The volume of fixed mass of a gas varies inversely as the pressure changes if the temperature is constant".
Mathematically;
P₁V₁ = P₂V₂
where P and V are pressure and volume, 1 and 2 represents initial and final states.
Substitute to find the V₂;
105 x 2.5 = 40.5 x V₂
Solving for V₂ gives 6.48L
