Answer: the electrons i.e their valence electron
Explanation: valence electron is the number of electron in the outermost shell of an atom. Infact it is the combining power of an element. The valence electron gives us a better understanding of how an element will react with other elements. This is the reason why elements with the same number of valence electron(s) are grouped together telling us that they exhibit similar chemical properties
Answer:
: The conductivity of electrolyte solutions: (a) 0.1 M NaCl (b) 0.05 M NaCl (c) 0.1 M HgCl2. An electrolyte solution conducts electricity because of the movement of ions in the solution (see above). The larger the concentration of ions, the better the solutions conducts. Weak electrolytes, such as HgCl2, conduct badly because they produce few ions when dissolved (low concentration of ions) and exist mainly in the form of molecules.
Explanation:
Answer:
HI
H₂O
H₃O⁺
I⁻
Explanation:
Bronsted-Lowry acids are chemicals that can donate protons, and Bronsted-Lowry bases are chemicals that can accept them. Conjugate bases and acids are the resulting effect of losing or gaining a proton in the form of H⁺.
<h3>
Answer:</h3>
825 mL
<h3>
Explanation:</h3>
<u>We are given;</u>
- Molarity of HCl is 0.200 M
- Mass of CaCO₃ is 8.25 g
- The equation of the reaction as;
CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
We are required to calculate the volume of the Acid that reacted.
<h3>Step 1: Determine the moles of CaCO₃ that reacted;</h3>
We know that;
Moles = Mass ÷ molar mass
Molar mass CaCO₃ is 100.1 g/mol
Therefore;
Moles of CaCO₃ = 8.25 g ÷ 100.1 g/mol
= 0.0824 moles
<h3>Step 2: Determine the moles of HCl that reacted;</h3>
From the reaction, 1 mole of CaCO₃ reacts with 2 moles of HCl
Therefore;
Moles of HCl = Moles of CaCO₃ × 2
= 0.0824 moles × 2
= 0.1648 moles
= 0.165 moles
<h3>Step 3: Determine the volume of HCl </h3>
We know that, Molarity = Moles ÷ Volume
Rearranging the formula;
Volume = Moles ÷ Molarity
Therefore;
Volume of HCl = 0.165 moles ÷ 0.200M
= 0.825 L
But, 1 L = 1000 mL
= 825 mL
Therefore, the volume of HCl that reacted with CaCO₃ 825 mL