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Mariana [72]
3 years ago
7

Can somebody help me with this problem

Mathematics
1 answer:
vovikov84 [41]3 years ago
5 0
What problem you need help in
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The diameter of a circle is 2 units. What is the radius of the circle
Luda [366]

Answer:

1

Step-by-step explanation:

The radius is half the size of the diameter.

2 / 2 = 1

3 0
3 years ago
Write y = x2 + 24x + 144 as a square of binomial.
irina1246 [14]

Answer:

y=(x+12)^2\\

Step-by-step explanation:

To write a quadratic equation into binomial form we can compare the equation into the completing square form of a quadratic equation like this ,

y=a(x-h)^2+k

now since,

y=x^2+24x+144

we can equate both the equations from left hand side to right hand side like this,

x^2+24x+144=a(x-h)^2+k\\

now we solve,

x^2+24x+144=a(x-h)^2+k\\x^2+24x+144=a((x)^2-2(x)(h)+(h)^2)+k\\x^2+24x+144=a(x^2-2hx+h^2)+k\\x^2+24x+144=ax^2-2ahx+ah^2+k\\

now we compare the coefficients of x^2:

1 = a\\

now we compare the coefficients of x :

24=-2ah\\24=-2(1)h\\24=-2h\\\frac{24}{-2}=h\\-12=h\\

now we compare the constants , (constants are the letters which are not associated with any variable in this case the variable is x)

144 = ah^2+k\\144=(1)(-12)^2+k\\144=(1)(144)+k\\144=144+k\\144-144=k\\0=k\\

so now the value we got all the values for the completing square form we plug those in , a = 1 , h = -12 , k = 0 ,

y=a(x-h)^2+k\\y=1(x-(-12))^2+0\\y=(x+12)^2\\

this is the square of a binomial, if you want to verify if we expands this formula by the formula of (a + b)^2 we would get the same result. Thus this is the correct answer.

5 0
3 years ago
HELPP 25 POINTSS!!<br> ASAP
Liula [17]

Answer:

-1/4, 5/8

Step-by-step explanation:

:)

8 0
3 years ago
Read 2 more answers
Which situation can be represented by -85+85 choose all that apply
Anuta_ua [19.1K]
0 is most likely the answer. considering you didn’t add a picture or anything like that.
6 0
3 years ago
Find a cubic polynomial whose graph passes through the points (1,3),(2,−2),(3,−5),(4,0)
scoundrel [369]
The generic equation of a third degree polynomial is given by:
 y = ax ^ 3 + bx ^ 2 + cx + d
 We must make a system of equations to find the values of a, b, c, d.
 We have then:
 For (1, 3):
 3 = a (1) ^ 3 + b (1) ^ 2 + c (1) + d
 3 = a + b + c + d
 For (2, -2):
 -2 = a (2) ^ 3 + b (2) ^ 2 + c (2) + d
 -2 = 8a + 4b + 2c + d
 For (3, -5):
 
-5 = a (3) ^ 3 + b (3) ^ 2 + c (3) + d
 -5 = 27a + 9b + 3c + d
 For (4.0):
 0 = a (4) ^ 3 + b (4) ^ 2 + c (4) + d
 0 = 64a + 16b + 4c + d
 We obtain the following system of equations:
 3 = a + b + c + d
 -2 = 8a + 4b + 2c + d
 -5 = 27a + 9b + 3c + d
 0 = 64a + 16b + 4c + d
 Whose solution is:
 a = 1
 b = -5
 c = 3
 d = 4
 The polynomial will then be:
 y = x ^ 3 - 5x ^ 2 + 3x + 4
 Answer:
 
y = x ^ 3 - 5x ^ 2 + 3x + 4
4 0
3 years ago
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