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aksik [14]
3 years ago
5

a football player initially at rest accelerates uniformly as she runs down the field, travelling 17m (E) in 3.8s. What is her fi

nal velocity?
Physics
1 answer:
ikadub [295]3 years ago
6 0
X - Xo = 0.5(Vo +V)t

Xo cancels because it is 0 (she is at rest) 

17 = 0.5(0+V)3.8 

17 = 1.9V 

Final velocity is 8.94737 m/s 
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(III) A baseball is seen to pass upward by a window with a vertical speed of If the ball was thrown by a person 18 m below on th
Ghella [55]

Answer:

<em><u>Assuming that the vertical speed of the ball is 14 m/s</u></em> we found the given values:

a) V₀ = 23.4 m/s

b) h = 27.9 m

c) t = 0.96 s

d) t = 4.8 s

 

Explanation:

a) <u>Assuming that the vertical speed is 14 m/s</u> (founded in the book) the initial speed of the ball can be calculated as follows:  

V_{f}^{2} = V_{0}^{2} - 2gh

<u>Where:</u>

V_{f}: is the final speed = 14 m/s

V_{0}: is the initial speed =?

g: is the gravity = 9.81 m/s²

h: is the height = 18 m

V_{0} = \sqrt{V_{f}^{2} + 2gh} = \sqrt{(14 m/s)^{2} + 2*9.81 m/s^{2}*18 m} = 23.4 m/s  

b) The maximum height is:

V_{f}^{2} = V_{0}^{2} - 2gh

h = \frac{V_{0}^{2}}{2g} = \frac{(23. 4 m/s)^{2}}{2*9.81 m/s^{2}} = 27.9 m

c) The time can be found using the following equation:

V_{f} = V_{0} - gt

t = \frac{V_{0} - V_{f}}{g} = \frac{23.4 m/s - 14 m/s}{9.81 m/s^{2}} = 0.96 s

d) The flight time is given by:

t_{v} = \frac{2V_{0}}{g} = \frac{2*23.4 m/s}{9.81 m/s^{2}} = 4.8 s

         

I hope it helps you!    

3 0
4 years ago
A string attached to an airborne kite is maintained at an angle of 41 degrees with the horizontal. If a total of 152 m of string
satela [25.4K]

Answer:

The  horizontal displacement is  Adj  =  114.71 \ m

Explanation:

From the question we are told that  

    The  angle at which the string is maintained is  \theta  =  41 ^o

      The length of string reeled in is  l  = 152 \ m

     

Using the SOHCAHTOA formula

   We have that the hypotenuse(Hyp) is  l  =  152

Hence the  horizontal displacement of the kite  which is the Adjacent(Adj)  can be evaluated as  

     cos \theta  =  \frac{Adj}{Hyp }

substituting values

     cos(41)  =  \frac{Adj}{152}

=>   Adj  =  114.71 \ m

3 0
3 years ago
During a very quick stop, a car decelerates at 28.4 rad/s?. Assume the tires initially rotated in the positive direction and rad
Damm [24]

Answer:

a) 24

b) 3.3 sec

c) 29.8 m/s

d) 48.85 m

Explanation:

a)

α = angular acceleration = - 28.4 rad/s²

r = radius of the tire = 0.32 m

w₀ = initial angular velocity = 93 rad/s

w = final angular velocity = 0 rad/s

θ = angular displacement

Using the equation

w² = w₀² + 2αθ

0² = 93² + 2 (- 28.4) θ

θ = 152.3 rad

n = number of revolutions

Number of revolutions are given as

n = \frac{\theta }{2\pi }

n = \frac{152.3 }{2(3.14) }

n = 24

b)

t = time taken to stop

using the equation

w = w₀ + αt

0 = 93 + (- 28.4) t

t = 3.3 sec

c)

v₀ = initial velocity of the car

initial velocity of the car is given as

v₀ = r w₀ = (0.32) (93) = 29.8 m/s

d)

v = final velocity = 0 m/s

a = linear acceleration = rα = (0.32) (- 28.4) = - 9.09 m/s²

d = distance traveled by car before stopping

Using the equation

v² = v₀² + 2 a d

0² = 29.8² + 2 (- 9.09) d

d = 48.85 m

8 0
4 years ago
Electromagnetic Energy Example One Activity:
stich3 [128]
One type is microwaves

Microwaves are used for radio and radar communications
Also used to cook food
6 0
3 years ago
Read 2 more answers
Does the coefficient of kinetic friction depend on speed?
kolbaska11 [484]
It depends on speed because it is a part of a car
3 0
3 years ago
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