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2 years ago

Speed of a cycle 15 km per hour to the speed of scooter 30 km per hour. find the ratio

Mathematics

1 answer:

Andrei [34K]2 years ago

7 0

Answer:

Cycle : Scooter = 15 : 30

or, Cycle : Scooter = 1 : 2

Step-by-step explanation:

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What is true of the graph of two lines 3y-8=-5x and 6y=-10x+16

Murljashka [212]

Answer:

Both lines are equal (they are the same)

Step-by-step explanation:

Given

$3y - 8 = -5x$

$6y = -10x + 16$

Required

What is true about graph of both lines

Questions like this are better solved when there's option(s) to select from. However, some of the properties of line equation that I'll consider are to check if both lines are either parallel or perpendicular

To do this,

The first thing to do is to calculate the slope of both lines

$3y - 8 = -5x$

Add 8 to both sides

$3y - 8 + 8 = -5x + 8$

$3y = -5x + 8$

Divide both sided by 3

$\frac{3y}{3} = -\frac{5x}{3} + \frac{8}{3}$

$y = -\frac{5x}{3} + \frac{8}{3}$

The slope of the line is the coefficient of x;

$Slope = -\frac{5}{3}$

Solve for the y intercept; Let x = 0

$y = -\frac{5 * 0}{3} + \frac{8}{3}$

$y = 0 + \frac{8}{3}$

$y = \frac{8}{3}$

Solve for the x intercept; Let y = 0

$0 = -\frac{5x}{3} + \frac{8}{3}$

Subtract $\frac{8}{3}$ from both sides

$0 - \frac{8}{3} = -\frac{5x}{3} + \frac{8}{3} - \frac{8}{3}$

$- \frac{8}{3} = -\frac{5x}{3}$

Subtract both sides by $-\frac{3}{5}$

$-\frac{3}{5}*- \frac{8}{3} = -\frac{5x}{3} * -\frac{3}{5}$

$-\frac{3}{5}*- \frac{8}{3} = x$

$\frac{3}{5} * \frac{8}{3} = x$

$\frac{8}{5} = x$

$x = \frac{8}{5}$

------------------------------------------------------------------------------------------------------

$6y = -10x + 16$

Divide both sides by 6

$\frac{6y}{6} = -\frac{10x}{6} + \frac{16}{6}$

$y = -\frac{10x}{6} + \frac{16}{6}$

Simplify fractions to lowest term

$y = -\frac{5x}{3} + \frac{8}{3}$

The slope of the line is the coefficient of x;

$Slope = -\frac{5}{3}$

Solve for the y intercept; Let x = 0

$y = -\frac{5 * 0}{3} + \frac{8}{3}$

$y = 0 + \frac{8}{3}$

$y = \frac{8}{3}$

Solve for the x intercept; Let y = 0

$0 = -\frac{5x}{3} + \frac{8}{3}$

Subtract $\frac{8}{3}$ from both sides

$0 - \frac{8}{3} = -\frac{5x}{3} + \frac{8}{3} - \frac{8}{3}$

$- \frac{8}{3} = -\frac{5x}{3}$

Subtract both sides by $-\frac{3}{5}$

$-\frac{3}{5}*- \frac{8}{3} = -\frac{5x}{3} * -\frac{3}{5}$

$-\frac{3}{5}*- \frac{8}{3} = x$

$\frac{3}{5} * \frac{8}{3} = x$

$\frac{8}{5} = x$

$x = \frac{8}{5}$

-------------------------------------------------------------------------------------------------------

By comparing the slope, x intercept and y intercept of both lines;

It'll be observed that they have the same slope, x intercept and y intercept

This implies that both lines are equal; in other words, they are the same.

6 0

2 years ago

125% is equivalent to what number

babymother [125]

125 is equivalent to

1.25

1 1/4

Pick either one... 1.25 is more likely to be correct

6 0

2 years ago

Mr. Ramsey just finished bathing his kids, and now he is draining the tub. The tub contains 32 gallons of water and is draining

KIM [24]

The answer would be 11 gallons.

The tub starts with 32 gallons. Every minute it loses 3 gallons.

So after 1 minute it has lost 3 gallons. For example:
32-3= 29 Meaning that after 1 minute the tub has 29 gallons left.

Now you have to remember that the tub is draining for 7 minutes. So it is losing 3 gallons 7 times, because it loses 3 gallons each minute and there are 7 minutes.

We can use multiplication to find how many gallons the tub loses after 7 minutes. This sign “X” basically means “groups of”. We have 7 groups of 3, or
7 X 3

This is the same as saying we have 3, 7 times. Written like this:

3+3 +3 +3 +3 +3 +3 = 21

So after 7 minutes the tub has lost 21 gallons.

Now we take the original number of gallons and take away what was lost:

32-21=11

So there are 11 gallons left after 7 minutes.

Please let me know if you need any further explanation. Hope this helped.

7 0

1 year ago

Help Me Please I will give brainliest if correct!

il63 [147K]

Answer:

9 $c^{7}$