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3 years ago

Which equation represents the slope-intercept form of the line below? y intercept: 0, 8 slope : 1/2

Mathematics

1 answer:

Natali [406]3 years ago

6 0

Answer:

y = 1/2 x + 8

Step-by-step explanation:

We are given the y intercept and the slope, so we can write the equation using the slope intercept form

y = mx+b where m is the slope and b is the y intercept

y = 1/2 x + 8

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The equations of four lines are given. Identify which lines are parallel.

Stella [2.4K]

Lines 2 & 3 are parallel.

7 0

3 years ago

Which series of transformations will not map figure H onto itself

7nadin3 [17]

Answer:

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation $(x+0,y-2)$ will map vertices of the square into points

$(2,1)\rightarrow (2,-1);$
$(1,2)\rightarrow (1,0);$
$(2,3)\rightarrow (2,1);$
$(3,2)\rightarrow (3,0).$

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

$(2,-1)\rightarrow (2,3);$
$(1,0)\rightarrow (1,2);$
$(2,1)\rightarrow (2,1);$
$(3,0)\rightarrow (3,2)$

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation $(x+2,y-0)$ will map vertices of the square into points

$(2,1)\rightarrow (4,1);$
$(1,2)\rightarrow (3,2);$
$(2,3)\rightarrow (4,3);$
$(3,2)\rightarrow (5,2).$

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

$(4,1)\rightarrow (2,1);$
$(3,2)\rightarrow (3,2);$
$(4,3)\rightarrow (2,3);$
$(5,2)\rightarrow (1,2)$

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation $(x+3,y+3)$ will map vertices of the square into points

$(2,1)\rightarrow (5,4);$
$(1,2)\rightarrow (4,5);$
$(2,3)\rightarrow (5,6);$
$(3,2)\rightarrow (6,5).$

2nd transformation = reflection over y = -x + 7 will map vertices into points

$(5,4)\rightarrow (3,2);$
$(4,5)\rightarrow (2,3);$
$(5,6)\rightarrow (1,2);$
$(6,5)\rightarrow (2,1)$

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation $(x-3,y-3)$ will map vertices of the square into points

$(2,1)\rightarrow (-1,-2);$
$(1,2)\rightarrow (-2,-1);$
$(2,3)\rightarrow (-1,0);$
$(3,2)\rightarrow (0,-1).$

2nd transformation = reflection over y = -x + 2 will map vertices into points

$(-1,-2)\rightarrow (4,3);$
$(-2,-1)\rightarrow (3,4);$
$(-1,0)\rightarrow (2,3);$
$(0,-1)\rightarrow (3,2)$

These points are not the vertices of the initial square.

5 0

3 years ago

In the figure below, AMNO

NeX [460]

Given:

$\Delta MNO\cong \Delta PQR$

To find:

The length of QR.

Solution:

We have,

$\Delta MNO\cong \Delta PQR$

Then, $MN=PQ$ (CPCTC)

$10=4x-2$

$10+2=4x$

$12=4x$

Divide both sides by 4.

$\dfrac{12}{4}=x$

$3=x$

Similarity,

$MO=PR$ (CPCTC)

$2y+3=21$

$2y=21-3$

$2y=18$

Divide both sides by 2.

$y=9$

Now,

$x+y=3+9$

$x+y=12$

Therefore, the correct option is d.

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3 years ago

I NEED MENNTAL HAELP

vekshin1

Answer:

Ummm Lilly Are you the one that I was jus talkin too

Step-by-step explanation:

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2 years ago

A line that includes the point (4,3) has a slope of 8. What is its equation in point-slope form?

anzhelika [568]

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3 0

2 years ago