Niobium has Highest ionization energy.
<u>Explanation:</u>
The next ionization energy removes an electron from the same electron shell, which increases "ionization energy" due to "increased net charge"of the ion from which the electron is being removed.
Let's compare each of the metals first ionization energies,
Rubidium has its first ionization energy as 403 kJ / mol.
Zirconium has its first ionization energy as 660 KJ / mol.
Niobium has its first ionization energy as 664 KJ / mol.
From the given data above, we can infer that Rubidium has the least Ionization energy whereas Niobium has the highest Ionization energy. We can give the increasing order of the given elements as follows-
Rubidium < Zirconium < Niobium
Answer:
In the third tube, the concentration is 0.16 ug/mL
Explanation:
In the first step, the solution is diluted by 5. Then, the concentration will be
20 ug/mL / 5 = 4 ug/mL
Then, in the second step this 4 ug / ml solution is diluted by a factor of five again:
4 ug /ml / 5 = 0.8 ug/mL
This solution is then diluted again by 5 and the concentration in the third tube will be then:
0.8 ug/mL / 5 = <u>0.16 ug/mL </u>
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Another way to calculate this is to divide the original concentration by the dilution factor ( 5 in this case) elevated to the number of dilutions. In this case:
Concentration in the third tube = 20 ug/mL / 5³ = 0.16 ug/mL
The concentration of carbon monoxide at equilibrium is 0.209 M.
<h3>Concentration of each gas</h3>
CO2 = 2 mol/5 L = 0.4
H2 = 1.5 mol/5L = 0.3
<h3>ICE table</h3>
Create ICE table as shown below
CO2(g) + H2(g) ↔ CO(g) + H2O(g)
I 0.4 0.3 0 0
C - x - x x x
E 0.4 - x 0.3 - x x x
Kc = [CO][H₂O] / [CO₂][H₂]
2.5 = (x²)/(0.4 - x)(0.3 - x)
x² = 2.5(0.4 - x)(0.3 - x)
x² = 2.5(0.12 - 0.7x + x²)
x² = 0.3 - 1.75x + 2.5x²
0 = 1.5x² - 1.75x + 0.3
solve the quadratic equation using formula method;
x = 0.209
Thus, the concentration of carbon monoxide at equilibrium is 0.209 M.
Learn more about concentration here: brainly.com/question/17206790
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Unsaturated would be the correct answer.
