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AURORKA [14]
3 years ago
7

Solve the triangle. A = 32°, a = 19, b = 12

Mathematics
2 answers:
blagie [28]3 years ago
8 0
180 deggreeese or 31
romanna [79]3 years ago
7 0
180 deggreese or 31
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Determine the solutions of the equation. What solution
Vika [28.1K]

Answer: x=8

Width=8 inches

Length=13 inches

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Every 3 weeks 8 students will lose their metro cards... How many will lose it in 9 weeks
Marina86 [1]
First we must divide 9 by 3.

9/3 = 3

Then multiply it by 8

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7 0
3 years ago
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Find an equivalent expression for each expression by simplifying. (3x - 5y) + 7y
sertanlavr [38]
This question is quite simple really. They are basically asking you to combine like terms. You have two different figures with the variable y, so you just combine the them. It would then be 3x + 2y. You cannot simplify this equation any further since there is nothing to solve for or anymore like terms to combine.
4 0
3 years ago
PLEASE HELP! Explain your answer, THANK YOU!
Misha Larkins [42]

Answer:

-2/-3

Step-by-step explanation:

(75, 60) (45, 40)

75       60               since 75 is larger than 45, we subtract = -30

45       40               since 60 is larger than 40, we subtract = -20

= -20/-30

reduce

= -2/-3

3 0
3 years ago
A gate is made up of a rectangle and a semicircle, as shown. Find the area of the gate. Use 3.14 for .Round your answer to the n
allochka39001 [22]

Answer:

<em>797.0ft²</em>

Step-by-step explanation:

<u>Find a related diagram attached</u>

Area of the gate = Area of the semicircle + Area of the Rectangle

Area of the semicircle = πr²/2

r is the radius

From the diagram, radius r = 20/2 = 10ft

Area of the semicircle = 3.14(10)²/2

Area of the semicircle = 3.14(100)/2

Area of the semicircle = 314/2

Area of the semicircle = 157ft²

Area of the rectangle = Length * Width

Area of the rectangle = 20*32

Area of the rectangle = 640ft²

Area of the gate = 157 + 640

Area of the gate = 797ft²

<em>Hence the area of the gate is 797.0ft²</em>

7 0
3 years ago
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