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3 years ago

Ammonium hydroxide has the chemical formula NH4OH. Which statement is true about ammonium hydroxide?

Physics

2 answers:

omeli [17]3 years ago

6 0

Answer:

The correct answer is option C. Each molecule contains seven atoms.

Explanation:

Hi!

Let's solve this!

The compound is:

NH4OH

Let's analyze each of the options:

A. It is an element: it is not an element, it is a molecule composed of different elements.

B. It contains four elements: it only contains three elements, nitrogen, hydrogen and oxygen.

C. Each molecule contains seven atoms: it contains a nitrogen atom, an oxygen atom and five hydrogen atoms, the sum of seven atoms.

D. Each molecule contains four hydrogen atoms: each molecule contains five hydrogen atoms.

After the analysis, we conclude that the correct answer is option C. Each molecule contains seven atoms.

AfilCa [17]3 years ago

3 0

C........................

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3 years ago

Complete the sentence-

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Answer:

Friction always acts opposite to the motion.

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3 years ago

Read 2 more answers

4. Johnny exerts a 3.55 N rightward force on a 0.200-kg box to accelerate it across a low-friction track. If the total resistanc

Anon25 [30]

a) $15.2 m/s^2$

b) 1.96 N

c) 1.96 N

Explanation:

To find the box's acceleration, we have to find first the net force acting on the box in the horizontal direction.

We have:

- The forward force of 3.55 N

- The backward, resistive force of 0.52 N

So, the net force forward is

$\sum F=3.55-0.52=3.03 N$

Now we can find the acceleration by using Newton's second law of motion, which states that:

$\sum F=ma$

where

m = 0.200 kg is the mass of the box

a is its acceleration

And solving for a, we find the acceleration:

$a=\frac{\sum F}{m}=\frac{3.03}{0.200}=15.2 m/s^2$

The gravitational force on an object is the force with which the object is pulled towards the ground by the Earth.

It is given by

$W=mg$

where

m is the mass of the object

g is the gravitational field strength

In this problem we have

m = 0.200 kg is the mass of the box

$g=9.8 m/s^2$ is the gravitational field strength

So, the gravitational force on the box is

$W=(0.200)(9.8)=1.96 N$

The normal force is the reaction force exerted by the floor on the box, in the upward direction.

In order to find the magnitude of this force, we apply Newton's second law of motion along the vertical direction.

We have two forces in this direction:

- The gravitational force, W, downward

- The normal force, N, upward

So the net force is

$\sum F=N-W$

According to Newton's second law,

$\sum F=ma$

However, the box is at rest in the vertical direction, so the vertical acceleration is zero:

$a=0$

This means that the net force is zero:

$\sum F=0$

And so, we can find the normal force:

$N-W=0\\N=W=1.96 N$

4 0

3 years ago

When a car of mass 1167 kg accelerates from 10.0 m/s to some final speed, 4.00  10 5J of work are done. Find this final speed.

Akimi4 [234]

Mass=1167kg
Initial velocity=u=10m/s
Acceleration=a=4m/s^2
Work done=105J=W
Final velocity=v=?
Force=F
Distance=d

Apply Newton's second law

$\\ \tt\hookrightarrow F=ma$

$\\ \tt\hookrightarrow F=1167(4)=4668N$

Now

$\\ \tt\hookrightarrow W=Fd$

$\\ \tt\hookrightarrow d=\dfrac{W}{F}$

$\\ \tt\hookrightarrow d=\dfrac{105}{4668}$

$\\ \tt\hookrightarrow d=0.022m$

Now

d be s

According to third equation of kinematics

$\\ \tt\hookrightarrow v^2=u^2+2as$

$\\ \tt\hookrightarrow v^2=10^2+2(4)(0.022)$

$\\ \tt\hookrightarrow v^2=100+8(0.022)$

$\\ \tt\hookrightarrow v^2=100+0.176$

$\\ \tt\hookrightarrow v^2=100.176$

$\\ \tt\hookrightarrow v=10.001m/s$

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2 years ago

Using information about natural laws, explain why some car crashes produce minor injuries and others produce catastrophic injuri

kicyunya [14]

The forces in some car crashes are greater than others; therefore, the body can be more severely injured by greater and more powerful forces. I hope this helped! :^)

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3 years ago