A hypothesis is an educated guess. It's your own opinion!
Answer:
ε = 2 V/cm
Explanation:
To calculate the mobility inside this bar, we just need to apply the expression that let us determine the mobility. This expression is the following:
ε = ΔV / L
Where:
ε: Hole mobility inside the bar
ΔV: voltage applied in the bar
L: Length of the bar
We already have the voltage and the length so replacing in the above expression we have:
ε = 2 V / 1 cm
<h2>
ε = 2 V/cm</h2><h2>
</h2>
The data of the speed can be used for further calculations, but in this part its not necessary.
Hope this helps
I believe the answer is a
Answer:
B) 0.3Hz
Explanation:
I just took the test i hope i helped and i hope you pass the test
Answer:
A. Zero
Explanation:
Given data,
The charge of the test charge, q = 1 C
The distance the charge moved against the filed of intensity, x = 30 cm
= 0.3 m
The electric field intensity, E = 50 N/C
The energy stored in the charge at 0.3 m is given by the formula,
V = k q/r
Where,
= 9 x 10⁹ Nm²C⁻²
The charge is moved from the potential V₁ to V₂ at 30 cm
Substituting the given values in the above equation
V₁ = 9 x 10⁹ x 30 / 0.3
= 1.5 x 10¹² J
And,
V₂ = 1.5 x 10¹² J
The energy stored in it is,
W = V₂ - V₁
= 0
Hence, the energy stored in the charge is, W = 0
