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poizon [28]
3 years ago
11

The gear motor can develop to 1/2 hp when it turns at 300 rev/min. If the shaft has a diameter of 1/2 in. determine the maximum

shear stress in the shaft
Physics
1 answer:
White raven [17]3 years ago
5 0

Answer:

145.902 psi

Explanation: Given power = 0.5 hp= 225 ft-lb/sec, N= 300 rpm shaft

dia= 0.5 inch

We know that power transmitted by circular shaft is

P=\frac{2piNT}{60}

now putting the values to find torque

⇒T=\frac{60P}{2piN}=\frac{60\times225}{2\times pi\times300}

⇒T=7.16 lb-ft

now to calculate shear stress\tau=\frac{16T}{pi\timesd^{3} }

⇒\tau =\frac{16\times7.16}{pi\times0.5^3}

⇒\tau=145.902 psi

hence maximum shear stress in the shaft is 145.902 psi

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Answer:

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Of course, the intensity of the magnetic field is proportional to the current, given by:

B = (μ*I)/(2*π*r)

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Now remember that for a resistor:

R = ρ*L/A

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3 0
3 years ago
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Answer:

1.736m/s²

Explanation:

According to Newton's second law;

\sum F_x = ma_x\\

Fm - Ff = ma_x\\ where;

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The equation becomes;

Fm - Ff = ma_x\\Fm - \mu mg = ma\\

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Fm - \mu mg = ma\\70 - 0.18(20)(9.8) = 20a\\70-35.28 = 20a\\34.72 = 20a\\a = \frac{34.72}{20}\\a =  1.736m/s^2\\

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3 years ago
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