Question

The gear motor can develop to 1/2 hp when it turns at 300 rev/min. If the shaft has a diameter of 1/2 in. determine the maximum shear stress in the shaft

Answer 1

Answer:

145.902 psi

Explanation: Given power = 0.5 hp= 225 ft-lb/sec, N= 300 rpm shaft

dia= 0.5 inch

We know that power transmitted by circular shaft is

$P=\frac{2piNT}{60}$

now putting the values to find torque

⇒$T=\frac{60P}{2piN}$$=\frac{60\times225}{2\times pi\times300}$

⇒T=7.16 lb-ft

now to calculate shear stress$\tau=\frac{16T}{pi\timesd^{3} }$

⇒$\tau =\frac{16\times7.16}{pi\times0.5^3}$

⇒$\tau$=145.902 psi

hence maximum shear stress in the shaft is 145.902 psi