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sergejj [24]
3 years ago
9

Given f(x) =3x-7, find f(x+1)+f(1)

Mathematics
1 answer:
ELEN [110]3 years ago
3 0

Answer:

3x - 8

Step-by-step explanation:

To find f(x + 1) substitute x = x + 1 into f(x)

f(x + 1) = 3(x + 1) - 7 = 3x + 3 - 7 = 3x - 4

Similarly

f(1) = 3(1) - 7 = 3 - 7 = - 4

Hence

f(x + 1) + f(1) = 3x - 4 - 4 = 3x - 8

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Mahnoor randomly selects times to walk into a local restaurant and observe the type of music being played She found that the res
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Type of music      Country  Rock & roll  Blues  

Observed number   11            17                 8      

Probabilities P(x)      11/36     17/36           8/36  

Step-by-step explanation:

The probabilities can be calculated as

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In the trapezoid at the right, BE= 2x-8, DE= x-4, and AC= x+2
Marta_Voda [28]

Answer:

A.  x = 5 (Equation below)

B. AC = 9 | BD = 9

Step-by-step explanation:

A. Since we know the diagonals of an isosceles trapezoid are congruent, we know that the two bottom parts of the diagonal BD (2x - 8 and x - 4) are congruent to the diagonal AC (x + 2) . This means you can just equal them together and get the value of x:

2x - 8 + x - 4 = x + 2

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3x = x + 14

2x = 14

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B. Just plug in 5 for x:

AC = x + 2 = 7 + 2 = 9

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Rufina [12.5K]

Answer:

  1. The instantaneous rate of increase of f(x) at x_{0} = 3 is 3.
  2. One possible equation of this line is y = 3x - 16.
  3. The line is tangent to the graph of y = f(x). The slope of the line is the same as the instantaneous rate of increase of f(x) at x_{0} = 3.

Step-by-step explanation:

<h3>1.</h3>

\begin{aligned}&\lim_{h\to 0}{\frac{f(3+h)-f(h)}{h}}\\ =&\lim_{h\to 0}\frac{1}{h} \cdot [(3^{3} + 3 \times 3^{2}h +3\times 3h^{2} + h^{3})- 4(3^{2} + 2\times 3h + h^{2}) + 2 \\[-1em] &\phantom{\lim_{h\to 0}\frac{1}{h}\cdot []} -(3^{3} -4\times 3^{2} + 2)]\\ = &\lim_{h \to 0}\frac{h^{3} + 5h^{2} +3h}{h}\\=& \lim_{h \to 0}{h^{2}} + \lim_{h \to 0}{5h} + \lim_{h\to 0}{3}\\ =& 3\end{aligned}.

<h3>2.</h3>

f(3) = 3^{3} - 4\times 3^{2} + 2 =-7.

In other words, the graph of y = f(x) passes through the point (3, -7) where x = 3.

The point-slope form of a line in a cartesian plane is:

y - y_0 = m (x - x_0).

For this line,

(3, -7) is the point on the line, while

3 is the slope of the line.

The equation of this line will thus be

y - (-7) = 3(x - 3).

That's equivalent to

y = 3x - 16.

<h3>3.</h3>

Refer to the diagram attached. The line touches the graph of y = f(x) at x = 3 without crossing it. The line here is thus a tangent to the graph of y = f(x) at x = 3. The slope of the line represents the instantaneous rate of increase of f(x) at x_{0} = 3.

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