Ask question

Ask question

All categories

3 years ago

9

Simplify.

sqrt[3]{125x^{21} y^{33} }" alt="\sqrt[3]{125x^{21} y^{33} }" align="absmiddle" class="latex-formula">

1 answer:

In-s [12.5K]3 years ago

6 0

Answer:

5x^7y^11.

Step-by-step explanation:

∛(125x^21 y^33)

The cube root = 'to the power 1/3' so we have:

125^1/3 * x^(21*1/3) * y^(33*1/3)

5x^7y^11.

You might be interested in

Anyone in connections academy algebra 2 or someone else that can help me with some problems? Here is the first: Let f(x)=2x^2+x-

sergiy2304 [10]

F(x)/g(x) = (2x +3)(x -1)/(x -1) = 2x +3 . . . . . x ≠ 1

The domain of (f/g)(x) is all real numbers except 1.

_____
The domain of any rational function necessarilly excludes any values that make the function undefined, that is, that make the denominator zero.

3 0

3 years ago

What is 2/3 x 6 in simplest form?

iris [78.8K]

Answer:

It's 4

Step-by-step explanation:

every integer is the rational number, so, a whole number 6 can be written as 6/1. 2/3 x 6 = 12/3 as simplified as 4/1 in fraction form.

3 0

3 years ago

Graph the inequality y ≤ |x + 2|. Which point is NOT part of the solution?

ddd [48]

Answer:

(-1 , 2) Not part of the solution

Step-by-step explanation:

from the graph:

(0 , 0) in the red part ⇒ it's a solution

(-1 , -2) in the red part ⇒ it's a solution

(1 , 2) in the red part ⇒ it's a solution

(-1 , 2) in the red part ⇒ it's Not a solution

5 0

3 years ago

Read 2 more answers

Use technology or a z-score table to answer the question. The weights of members of a baseball league are normally distributed w

kirza4 [7]

Answer:

100

Step-by-step explanation:

The attached "technology" shows that about 0.8327 of the league will weigh 165 pounds or more. That number is ..

0.8327 × 120 members = 99.92 members ≈ 100 members

About 100 members of the league will weigh 165 pounds or more.

7 0

3 years ago

Since the area under the normal curve within two standard deviations of the mean is 0.95, the area under the normal curve that c

alukav5142 [94]

Answer:

$X \sim N (\mu ,\sigma)$

And for this case we know this condition:

$P(\mu-2\sigma$

By the complement rule we know that:

$P(X< \mu -2\sigma \cup X>\mu +2\sigma) = 1-0.95=0.05$

But since the distribution is symmetrical we know that:

$P(X\mu +2\sigma) = 0.025$

So then the statement for this case is FALSE.

b. False

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

For this case if we define the random variable of interest X and we know that this random variable follows a normal distribution:

$X \sim N (\mu ,\sigma)$

And for this case we know this condition:

$P(\mu-2\sigma$

By the complement rule we know that:

$P(X< \mu -2\sigma \cup X>\mu +2\sigma) = 1-0.95=0.05$

But since the distribution is symmetrical we know that:

$P(X\mu +2\sigma) = 0.025$

So then the statement for this case is FALSE.

b. False

5 0

3 years ago