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2 years ago

In ΔIJK, k = 7.6 cm, j = 7.5 cm and ∠J=116°. Find all possible values of ∠K, to the nearest 10th of a degree.

Mathematics

1 answer:

Andre45 [30]2 years ago

7 0

Answer:

No Possible Triangles

Step-by-step explanation:

Deltamath

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Consider the graph below, and identify the piecewise function that describes it. An image of a graph. Question 12 options: f(x)=

serious [3.7K]

Answer:

20000

Step-by-step explanation:

HOPED THIS HELPED

A brainlyist is always appreciated

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2 years ago

7x ^ 3 - 4x ^ 2 - x + 4 is a polynomial. a Write the coefficient of x ^ 2 . What is the degree of the polynomial ?

Gala2k [10]

Answer:

coefficient of x^2 is -4

and degree of polynomial is 3

3 0

2 years ago

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Use the fundamental identities and appropriate algebraic operations to simplify the following expression. (18 +tan x) (18-tan x)

andrezito [222]

Answer:

a) $\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right)=325$

b) The lowest point of $y=\cos \left(x\right)$ , $0\leq x\leq 2\pi$ is when x = $\pi$

Step-by-step explanation:

a) To simplify the expression $\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right)$ you must:

Apply Difference of Two Squares Formula: $\left(a+b\right)\left(a-b\right)=a^2-b^2$

$a=18,\:b=\tan \left(x\right)$

$\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)=18^2-\tan ^2\left(x\right)=324-\tan ^2\left(x\right)$

$324-\tan ^2\left(x\right)+\sec ^2\left(x\right)$

Apply the Pythagorean Identity $1+\tan ^2\left(x\right)=\sec ^2\left(x\right)$

From the Pythagorean Identity, we know that $1=-\tan ^2\left(x\right)+\sec ^2\left(x\right)$

Therefore,

$324[-\tan ^2\left(x\right)+\sec ^2\left(x\right))]\\324[+1]\\325$

b) According with the below graph, the lowest point of $y=\cos \left(x\right)$ , $0\leq x\leq 2\pi$ is when x = $\pi$

3 0

3 years ago

The diameter of a circle is 3 ft. Find its area to the nearest tenth.

tatiyna

Answer:

A= 7.07ft squared

Step-by-step explanation:

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2 years ago

What is the slope of the line on the graph below? On a coordinate plane, a line goes through points (negative 2, negative 3), (n

Anestetic [448]

Answer:

Step-by-step explanation:

We can use 2 points to find the slope

m = (y2 -y1)/(x2-x1)

Using ( 0,1) and (1,3)

= (3-1)/(1-0)

= 2/1

= 2

7 0

2 years ago

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