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3 years ago

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Mathematics

1 answer:

Allushta [10]3 years ago

6 0

Answer:

why you color out the first part? what exctly is the question?

Step-by-step explanation:

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What is 5,836,197 rounded to the nearest hundred

olga nikolaevna [1]

Answer:

Rounded to the nearest hungered is 5,836,200

6 0

3 years ago

A triangle has sides measuring 2 and 7 of X represents the length in inches of the third side, which inequality gives the range

Nat2105 [25]

Answer:

The inequality range of X is determined as 5 < X < 9

Step-by-step explanation:

Given;

first length of the triangle = 2 inches

second length of the triangle = 7 inches

third length of the triangle = X

From the third length rule of a triangle, the following inequality range will be applied to determine the length of "X";

The third length of the triangle must be greater than the difference of the two known sides BUT less than the sum of the two known sides.

(7 - 2) < X < (7 + 2)

5 < X < 9

possible values of X = 6, 7, 8

Therefore, the inequality range of X is determined as 5 < X < 9

5 0

3 years ago

2 3/4 mi = how many fr

kirza4 [7]

Answer:

14520

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

What is the value of p. please explain.

xenn [34]

It's A
16 x 218=(16 x 200)+(16p)
3488=3200+16p
-16=3200 - 3488
-16p= -288
p=18

4 0

3 years ago

Read 2 more answers

If the quadratic formula is used to find the solution set of 3x2 + 4x - 2 = 0, what are the solutions?

7nadin3 [17]

Answer:

$x=\frac{-2}{3} \pm \frac{\sqrt{10}}{3}$

Step-by-step explanation:

Compare $ax^2+bx+c$ to $3x^2+4x-2$ .

We have $a=3,b=4,c=-2$ .

The quadratic formula is for solving equations of the form $ax^2+bx+c=0$ and is $x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$ .

So we are going to plug in our values in that formula to find our solutions,x.

If you want to notice it in parts you can.

Example I might break it into these parts and then put it in:

Part 1: Evaluate $b^2-4ac$

Part 2: Evaluate $-b$

Part 3: Evaluate $2a$

------Let's do these parts.

Part 1: $b^2-4ac=(4)^2-4(3)(-2)=16-12(-2)=16+24=40$ .

This part 1 is important in determining the kinds of solutions you have. It is called the discriminant. If it is positive, you have two real solutions. If it is negative, you have no real solutions (both of the solutions are complex). If it is 0, you have one real solution.

Part 2: $-b=-4$ since $b=4$ .