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Ksenya-84 [330]
4 years ago
11

The universe is expanding, all light from all galaxies is redshifted. True False

Physics
1 answer:
Serggg [28]4 years ago
3 0

I'm fairly sure that is true.



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The length of a planet's day is determined by it's
MatroZZZ [7]

Answer: "People will say the length of a day is determined by just the rotation rate of a planet, but that isn’t entirely true. The orbit around its sun also factors in. What we define as a day is the time between when the Sun is highest in the sky until the next time the Sun is at the highest point in the sky. This isn’t just the time it takes the Earth to rotate once on its axis, though. This is because, as the Earth is rotating, it’s also moving relative to the Sun"

3 0
3 years ago
Calculate the angular velocity of a clocks second hand, its minute hand, and its hour hand. State in Rad/s. What is its angular
fenix001 [56]

Second hand:

1 rev per minute = (2π radians/minute) x (1 min/60sec) = π/30 rad/sec

Minute hand:

1 rev per hour = (2π radians/hour) x (1 hr/3600 sec) = π/1800 rad/sec

Hour hand:

1 rev per 12 hours = (2π rad/12 hr) x (1 hr/3600 sec) = π/21,600 rad/sec

As long as the clock is in good working order, and the hands are turning steadily at their normal rate, there is no angular acceleration.

8 0
3 years ago
Suppose it takes a constant force a time of 6.0 seconds to slow a 2500 kg truck
erastovalidia [21]

Answer:

3.3\cdot 10^3\:\mathrm{N}

Explanation:

Impulse on an object is given by \mathrm{[impulse]}=F\Delta t.

However, it's also given as change in momentum (impulse-momentum theorem).

Therefore, we can set the change in momentum equal to the former formula for impulse:

\Delta p=F\Delta t.

Momentum is given by p=mv. Because the truck's mass is maintained, only it's velocity is changing. Since the truck is being slowed from 26.0 m/s to 18.0 m/s, it's change in velocity is 8.0 m/s. Therefore, it's change in momentum is:

p=2500\cdot 8.0=20,000\:\mathrm{kg\cdot m/s}.

Now we plug in our values and solve:

\Delta p=F\Delta t,\\F=\frac{\Delta p}{\Delta t},\\F=\frac{20,000}{6}=\fbox{$3.3\cdot 10^3\:\mathrm{N}$}(two significant figures).

6 0
3 years ago
Is F=mxa expressed in equation in newtons second law of motion?
kow [346]
Yes. That equation is exactly how we write Newton's second law nowadays. Note that the 'x' just means 'times'. It's not another variable. The equation could be written as simply. F = m a .
6 0
4 years ago
What do you notice about the wavelength versus the frequency of the wave?
Dominik [7]

<u>Answer:</u>

The number of complete wavelengths in a given unit of time is called frequency (f). As a wavelength increases in size, its frequency and energy (E) decrease. From these equations you may realize that as the frequency increases, the wavelength gets shorter. As the frequency decreases, the wavelength gets longer.

<u>Explanation:</u>

*can i be the brainliest*

6 0
4 years ago
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