Answer is miles sir your welcome it was simple
Answer:
Acceleration, ![767.08\ m/s^2](https://tex.z-dn.net/?f=767.08%5C%20m%2Fs%5E2)
Explanation:
Given that,
Height from a ball falls the ground, h = 17.3 m
It is in contact with the ground for 24.0 ms before stopping.
We need to find the average acceleration the ball during the time it is in contact with the ground.
Firstly, find the velocity when it reached the ground. So,
![v^2=u^2+2ah](https://tex.z-dn.net/?f=v%5E2%3Du%5E2%2B2ah)
u = initial velocity=0 m/s
a = acceleration=g
![v=\sqrt{2gh} \\\\v=\sqrt{2\times 9.8\times 17.3} \\\\v=18.41\ m/s](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B2gh%7D%20%5C%5C%5C%5Cv%3D%5Csqrt%7B2%5Ctimes%209.8%5Ctimes%2017.3%7D%20%5C%5C%5C%5Cv%3D18.41%5C%20m%2Fs)
It is in negative direction, u = -18.41 m/s
Let a is average acceleration of the ball. Consider, v = and u = -18.41 m/s.
![a=\dfrac{v-u}{t}\\\\a=\dfrac{0-18.41}{24\times 10^{-3}}\\\\a=767.08\ m/s^2](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7Bv-u%7D%7Bt%7D%5C%5C%5C%5Ca%3D%5Cdfrac%7B0-18.41%7D%7B24%5Ctimes%2010%5E%7B-3%7D%7D%5C%5C%5C%5Ca%3D767.08%5C%20m%2Fs%5E2)
So, the average acceleration of the ball during the time it is in contact is
.
Oxygen and Neon have the same number of valence electrons because both the compounds are in the same group and the outer orbital of both the compounds consists of 6 electrons
If your speed changes from 10 km/h to 6 km/h then
you have an acceleration.
Whether it's a positive or negative one completely depends
on which direction you decided to call the positive direction,
when you started considering your speed and its changes.
If you decided to call the direction in which you're traveling
the positive direction, then a decrease in your speed is a
negative acceleration.
But you could just as easily have said that you're traveling
in the negative direction. If you did that, then a decrease in
your speed would be a positive acceleration.
It's completely up to you, and how you define things.