The electrostatic force is directly proportional to the product of the charges, by Coulomb's law.
F α Qq
If the charges are now half the initial charges:
<span>F α (1/2)Q *(1/2)q
</span>
F α (1/4)Q<span>q
The new force when the charges are each halved is (1/4) the first initial force experienced at full charge.</span>
The answer is A. shorter wires
The circuit change when a wire is added is, an open circuit occurs and makes all bulbs turn off.
<h3>What is a closed circuit?</h3>
A closed circuit is a type of circuit connection in which the wire connection is complete and current flow occurs, turning the light bulbs on in the process.
<h3>What is an open circuit?</h3>
An open circuit is a type of circuit connection in which the wire connection is incomplete and current cannot flow, turning off the light bulbs.
Thus, the circuit change when the wire is added is, an open circuit occurs and makes all bulbs turn off.
Learn more about open circuit here: brainly.com/question/20351910
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Answer:
Technician A
Explanation:
Technician A is correct because, the hand force required is not supposed and even should not exceed 80 lb.
On the other hand, the foot force limit is even higher at 100 lb. Thus, the required foot force break should not exceed 100 lb. We are given 80 lb in the question, which is quite less than 100 lb. It could exceed 80, but must not exceed 100. Thus only Technician A is correct among them both.
