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Otrada [13]
3 years ago
9

 Which of the following levels of classification is the least specific?

Physics
1 answer:
Troyanec [42]3 years ago
4 0
Species is the least specific
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Draw the position vs. time graph for a person walking at a constant speed of 1m/s for 10 seconds. On the same axes, draw graph f
Leto [7]
In both scenarios, the position - time graph will be a linear graph, since the speed is constant, so your position is moving at a consistent pace.
7 0
3 years ago
Give an example of a theory scientists believed for a long time that was eventually proved false
jolli1 [7]
There are so many to choose from, I'll give you two. One is a big one. The other so/so. People used to believe the earth was flat and you would fall off, until Christopher Columbus sailed across. And another interesting one is the vulcan planet theory, which is that there was an extra planet between Mercury and T sun. however it turned out to be false. So there, need anymore just tell me.
6 0
3 years ago
Argon in the amount of 1.5 kg fills a 0.04-m3 piston cylinder device at 550 kPa. The piston is now moved by changing the weights
Arlecino [84]

Answer:

               275 kPa

Explanation:

             mass of the gas=m=1.5 kg

             initial volume if the gas=V₁=0.04 m³

             initial pressure of the gas= P₁=550 kPa

as the condition is given final volume is double the initial volume

             V₂=final volume

             V₂=2 V₁

As the temperature is constant

             T₁=T₂=T

\frac{P1V1}{T1}=\frac{P2 V2}{T2}

putting the values in the equation.

\frac{P1V1}{T1}=\frac{P2 *2V1}{T2}

P₂=\frac{P1}{2}

P₂=\frac{550}{2}

P₂=275 kPa

So the final pressure of the gas is 275 kPa.

           

3 0
4 years ago
Explain what will happen if an object has high momentum or low momentum and a force is applied?
Korvikt [17]

-- If the force is applied in the <em>same direction</em> as the object is moving, then the object's momentum in that direction will <em>increase</em>.

-- If the force is applied in the direction <em>OPPOSITE </em>to the way the object is moving, then the object's momentum will <em>decrease</em>.

-- In either case, the CHANGE in the object's momentum will be

(strength of the force) x (length of time the force is applied) .

This quantity is also called "impulse".

5 0
3 years ago
A charge of -3.02 μC is fixed in place. From a horizontal distance of 0.0377 m, a particle of mass 9.43 x 10^-3 kg and charge -9
Andreyy89

Answer:

d = 0.0306 m

Explanation:

Here we know that for the given system of charge we have no loss of energy as there is no friction force on it

So we will have

U + K = constant

\frac{kq_1q_2}{r_1} + \frac{1}{2}mv_1^2 = \frac{kq_1q_2}{r_2} + \frac{1}{2}mv_2^2

now we know when particle will reach the closest distance then due to electrostatic repulsion the speed will become zero.

So we have

\frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{0.0377} + \frac{1}{2}(9.43 \times 10^{-3})(80.4)^2 = \frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{r} + 0

7.05 + 30.5 = \frac{0.266}{r}

r = 7.08 \times 10^{-3} m

so distance moved by the particle is given as

d = r_1 - r_2

d = 0.0377 - 0.00708

d = 0.0306 m

6 0
3 years ago
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