Answer:
Linear function with rate of change/growth = 2.5, which agrees with the fourth statement listed in the answers options.
Step-by-step explanation:
Notice that both columns of reported x and y values are increasing.
Then examine how the given x-values increase:
-2, 2, 6, 10, 14 (in steps of 4 units)
and how their corresponding y-values increase:
-2, 8, 18, 28, 38 (in steps of 10 units)
therefore, if we do the rate of change for any pair
and
, we get the following constant rate of change:

Given that this relationship is valid for any pair of (x,y) values. we conclude that the rate of increase is constant, and therefore we are in the presence of a linear function, whose rate of change is 2.5
4 1/4 is greater than 4 3/11
Hope I helped!
~ Zoe
The answer is 10.5 pounds. No there is no other solutions.
24 divided by 1/4 = 6 lbs
24 divided by 1/8 = 3 lbs
24 divided by 1/16 = 1.5 lbs
6+3+1.5= 10.5 lbs of food
Answer:
40
Step-by-step explanation:
here is a trig calculator
http://www.carbidedepot.com/formulas-trigright.asp
i. 171
ii. 162
iii. 297
Solution,
n(U)= 630
n(I)= 333
n(T)= 168
i. Let n(I intersection T ) be X

<h3>ii.
n(only I)= n(I) - n(I intersection T)</h3><h3>
= 333 - 171</h3><h3>
= 162</h3>
<h3>
iii. n ( only T)= n( T) - n( I intersection T)</h3><h3>
= 468 - 171</h3><h3>
= 297</h3>
<h3>
Venn- diagram is shown in the attached picture.</h3>
Hope this helps...
Good luck on your assignment...