A new car is purchased for 23900 dollars. The value of the car depreciates at 14.25% per year. To the nearest tenth of a year, h
2 answers:
Answer:
The value of the car will be 6100 dollars in 8.8 years
Step-by-step explanation:
Present value of car = $23900
The value of the car depreciates at 14.25% per year
Let x be no. of years in which the value of the car becomes 6100 dollars
Formula:
Substitute the values :
Hence the value of the car will be 6100 dollars in 8.8 years
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Answer:
a.) Between 0.5 and 3 seconds.
Step-by-step explanation:
So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.
If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.
Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.
So, the answer is a.) between 0.5 and 3 seconds.
