A new car is purchased for 23900 dollars. The value of the car depreciates at 14.25% per year. To the nearest tenth of a year, h
2 answers:
Answer:
The value of the car will be 6100 dollars in 8.8 years
Step-by-step explanation:
Present value of car = $23900
The value of the car depreciates at 14.25% per year
Let x be no. of years in which the value of the car becomes 6100 dollars
Formula:
Substitute the values :
Hence the value of the car will be 6100 dollars in 8.8 years
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Answer:
65.56°
Step-by-step explanation:
We know that if we take dot product of two vectors then it is equal to the product of magnitudes of the vectors and cosine of the angle between them
That is let p and q be any two vectors and A be the angle between them
So, p·q=|p|*|q|*cosA
⇒
Given u=-8i-3j and v=-8i+8j
let A be angle before u and v
therefore,
⇒
Therefore angle between u and v is 65.56°
Answer:
Lower limit: 113.28
Upper limit: 126.72
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Middle 60%
So it goes from X when Z has a pvalue of 0.5 - 0.6/2 = 0.2 to X when Z has a pvalue of 0.5 + 0.6/2 = 0.8
Lower limit
X when Z has a pvalue of 0.20. So X when
Upper limit
X when Z has a pvalue of 0.80. So X when