In decimal form=-7.37
In fraction form plzz refer to the attachment
If the largest integer drawn among the four cards is 5, then that means that 3 of the cards drawn are from the set {1, 2, 3, 4}. The number of ways of selecting 3 cards from 4 cards is given by:
![^4C_3=4](https://tex.z-dn.net/?f=%5E4C_3%3D4)
If the largest integer drawn among the four cards is 6, then that means that 3 of the cards drawn are from the set {1, 2, 3, 4, 5}. The number of ways of selecting 3 cards from 5 cards is given by:
![^5C_3=10](https://tex.z-dn.net/?f=%5E5C_3%3D10)
If the largest integer drawn among the four cards is 7, then that means that 3 of the cards drawn are from the set {1, 2, 3, 4, 5, 6}. The number of ways of selecting 3 cards from 6 cards is given by:
![^6C_3=20](https://tex.z-dn.net/?f=%5E6C_3%3D20)
Therefore, <span>the number of selections grace could make if the largest integer drawn among the four cards is either a 5, a 6 or a 7 is given by 4 + 10 + 20 = 34 selections.</span>
If William has 3^3 baseball cards that means he has 3x3x3 baseball cards which is 27. 4^3 football cards is 4x4x4 so he has 64 of those. 64 + 27 = 91 so that’s how many cards he has in total
12 ÷ 3/4:
First, there are many ways to divide a whole number by a fraction. In my way, I take acknowledgment to the rules. There are other ways to do this, like the reciprocal way. To first get started, I'm going to give you the rule which is: (a ÷ b/c = a × c/b). We can now replace our numbers in the variables place.
![12 \times \frac{4}{3}](https://tex.z-dn.net/?f=12%20%5Ctimes%20%20%5Cfrac%7B4%7D%7B3%7D%20)
Second, we can simplify. To do so, (12 × 4 = 48). 48 is our new numerator while we keep the denominator we started out with (3).
![\frac{48}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B48%7D%7B3%7D%20)
Third, this is where long division comes in handy. I can't exactly do it on a website, but I am going to try. It is best if done on a piece of paper.
![\Mydiv3{% $\strut#$\kern.25em\smash{\raise.3ex\hbox{$\big)$}}$\mkern-8mu \overline{\enspace\strut#48}$} \\ \sf Multiply \ 4 \div \ 3 =1 \ (remainder \ 1) \\ \sf Bring \ down \ 8 \\ \sf 18 \div 3 = 6 \\ \sf 48 \div 3 = 16](https://tex.z-dn.net/?f=%5CMydiv3%7B%25%0A%24%5Cstrut%23%24%5Ckern.25em%5Csmash%7B%5Craise.3ex%5Chbox%7B%24%5Cbig%29%24%7D%7D%24%5Cmkern-8mu%0A%20%20%20%20%20%20%20%20%5Coverline%7B%5Censpace%5Cstrut%2348%7D%24%7D%20%5C%5C%20%5Csf%20Multiply%20%5C%204%20%5Cdiv%20%5C%203%20%3D1%20%5C%20%28remainder%20%5C%201%29%20%5C%5C%20%5Csf%20Bring%20%5C%20down%20%5C%208%20%5C%5C%20%5Csf%2018%20%5Cdiv%203%20%3D%206%20%5C%5C%20%5Csf%2048%20%5Cdiv%203%20%3D%2016)
Answer:
The median is the number in the middle of a sorted list.
So we need to arrange the given numbers, $699, $826, $839,
$880, $965, $1,087.
Since the givenhas 6 numbers, finding the median will be
the average of the two numbers in the middle.
$839 + $880 = 1719 then divide this by 2 = 859.5
So there are 3 numbers that are below the median and these
are $699, $826, and $839.