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Schach [20]
3 years ago
12

What is it asking me to put in the chart

Mathematics
1 answer:
cluponka [151]3 years ago
6 0
You basically have to count how many days received the amount of mail listed in the left column. Then out of the total amount of mail received, you would compute the fraction of the days during which a given amount of mail was received.


For instance, on every day, at least 5 pieces of mail were counted, so there are 0 days on which 0-4 pieces of mail were received.

On the other hand, on days 5-7 (15, 18, 19), the amount of mail received fell within the 15-19 range. This means out of 7 days, 15-19 pieces of mail were received on 3 of those days. So the frequency with which this occurred was \dfrac37\approx0.43.

So what you should get in the right column is
\begin{matrix}0-4&|&\frac07=0\\\\5-9&|&\frac27\approx0.29\\\\10-14&|&\frac27\approx0.29\\\\15-19&|&\frac37\approx0.43\end{matrix}
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What did I do wrong?!
Lena [83]
(3n-2) x (4n+1) =0

All you need to do is to find what value of n makes each factor equal 0.

First Term:
3n-2 = 0
3n = 2
n = 2/3

Second Term:

4n+1 = 0
4n = -1
n = -1/4

n ={2/3, -1/4}
5 0
3 years ago
What is the smallest distance between the origin and a point on the graph of:y=1/sqrt(2)*(x^2-8)
AleksAgata [21]
What we are being asked here is to simply minimize distance. Also, note that we can write
f
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y
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Now, what is this "distance?" How do we find it? Well, if you think back to Algebra I or Geometry, you'll remember that the distance between two points
(
x
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2
. For example, the distance between the points
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2
+
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4
−
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)
2
=
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Ok, so what is
(
x
1
,
y
1
)
and
(
x
2
,
y
2
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in our example?
(
x
1
,
y
1
)
is simple - it's just the point given in the problem,
(
4
,
0
)
. Because we don't know what
x
2
is, we'll just call it
x
for now. As for
y
2
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y
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x
, we'll call it
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x
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Our formula then becomes:
√
(
√
x
−
0
)
2
+
(
x
−
4
)
2
=
√
(
√
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2
)
+
x
2
−
8
x
+
16
=
√
x
+
x
2
−
8
x
+
16
=
√
x
2
−
7
x
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We are being asked to minimize this distance, which we'll call
s
to make the following calculations easier. To minimize something, we have to take its derivative, so let's start there:
s
=
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x
2
−
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x
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=
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−
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x
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1
2

d
s
d
x
=
(
2
x
−
7
)
⋅
1
2
(
x
2
−
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x
+
16
)
1
2
→
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d
s
d
x
=
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x
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7
2
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x
2
−
7
x
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0
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x
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0
=
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x
−
7
2
√
x
2
−
7
x
+
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=
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x
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y
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y
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2
+
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2
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4
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2
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units
5 0
3 years ago
Solve for x. −6 = 3/8 x
Marina CMI [18]

Answer:

x = -16

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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svetoff [14.1K]
30x20=600
You mean this lovely?
7 0
4 years ago
Read 2 more answers
Maggie puts together two isosceles triangles so that they share a base, creating a kite. Each leg of the upper triangle measures
Wittaler [7]
(See attached)
AO^2 = side a^2 - BO^2
AO^2 = 41^2 -40^2
AO^2 = 1,681 -1600
AO^2 = 81
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DO^2 = side b^2 -BO^2
DO^2 = 50^2 -40^2
DO^2 = 2,500 -1,600
DO^2 = 900
DO = 30

Diagonal AD = AO + DO = 9 + 30 = 39 inches

Source:
http://www.1728.org/quadkite.htm


5 0
3 years ago
Read 2 more answers
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