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Over [174]
3 years ago
13

A system of equations is shown below: Equation A: 4c = d – 8 Equation B: c = 5d + 8 Which of the following steps should be perfo

rmed to eliminate variable d first?
a. Multiply equation B by 4.
b. Multiply equation A by –5.
c. Multiply equation A by 4.
d. Multiply equation B by 5.
Mathematics
2 answers:
ozzi3 years ago
8 0
You would want to multiply equation a by -5 so you can eliminate by addition
Doss [256]3 years ago
6 0
B is the correct answer... Hope I'd helped!
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Step-by-step explanation:

9 {x}^{3} {y}^{2}  - 4x {y}^{4}  \\  = x {y}^{2} (9 {x}^{2}  - 4 {y}^{2} )

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Solve the system by substitution.<br> [-2.5x+y = 13.5<br> 12.25x - y=-12.25
IrinaK [193]

Answer:

x = 5/39 , y = 539/39

Step-by-step explanation:

Solve the following system:

{y - 2.5 x = 13.5

12.25 x - y = -12.25

In the first equation, look to solve for y:

{y - 2.5 x = 13.5

12.25 x - y = -12.25

y - 2.5 x = y - (5 x)/2 and 13.5 = 27/2:

y - (5 x)/2 = 27/2

Add (5 x)/2 to both sides:

{y = 1/2 (5 x + 27)

12.25 x - y = -12.25

Substitute y = 1/2 (5 x + 27) into the second equation:

{y = 1/2 (5 x + 27)

1/2 (-5 x - 27) + 12.25 x = -12.25

(-5 x - 27)/2 + 12.25 x = 12.25 x + (-(5 x)/2 - 27/2) = 9.75 x - 27/2:

{y = 1/2 (5 x + 27)

9.75 x - 27/2 = -12.25

In the second equation, look to solve for x:

{y = 1/2 (5 x + 27)

9.75 x - 27/2 = -12.25

9.75 x - 27/2 = (39 x)/4 - 27/2 and -12.25 = -49/4:

(39 x)/4 - 27/2 = -49/4

Add 27/2 to both sides:

{y = 1/2 (5 x + 27)

(39 x)/4 = 5/4

Multiply both sides by 4/39:

{y = 1/2 (5 x + 27)

x = 5/39

Substitute x = 5/39 into the first equation:

{y = 539/39

x = 5/39

Collect results in alphabetical order:

Answer: {x = 5/39 , y = 539/39

5 0
3 years ago
What is the following product?
jenyasd209 [6]

Answer:

10\sqrt{3}

Step-by-step explanation:

\sqrt{30} .\sqrt{10} \\= \sqrt{300} \\=\sqrt{100*3} \\= 10 \sqrt{3}

6 0
3 years ago
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