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zzz [600]
3 years ago
6

Two parallel lines, p and q, are cut by the transversal k as shown.

Mathematics
1 answer:
wariber [46]3 years ago
3 0

Answer:

corresponding

congruent

125 degrees

vertical angles

congruent

125 degrees

equal/similar

idk can you show me the options for this one?

transitive property <em>maybe</em> (this is for the line that says "the relationship between <1 and <3 is an example of the following rule)

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the line passing through the points A (-1,3k) and B (k , 3) is parallel to the line whose equation is 2y+3x=9. write down the co
vodomira [7]

Answer:

k = 3

Step-by-step explanation:

If the line passing through the points A (-1,3k) and B (k , 3) is parallel to the line whose equation is 2y+3x=9, then their slopes are equal

For coordinate AB;

slope m1 = 3 - 3k/k-(-1)

m1 = 3-3k/k+1

For the line 2y+3x = 9

2y = -3x + 9

y = -3/2 x + 9/2

Slope m2 = -3/2

Since m1 = m2

3-3k/k+1 = -3/2

Cross multiply

2(3-3k) = -3(k+1)

Expand

6 - 6k = -3k - 3

-6k+3k = -3 - 6

-3k = -9

k = -9/-3

k = 3

Hence the value of k is 3

4 0
3 years ago
Which fraction is bigger 30\100 or 3\10
Igoryamba
They are actually equivalent because 3 is a factor of 30 because 3x10 
And 10 is a factor of 100 so 10x10 
5 0
3 years ago
Read 2 more answers
To the nearest tenth -4 -2 1,3 find PQ
Triss [41]
Not really understanding what you are asking
4 0
3 years ago
How many duckling were swimming at the pond?
EleoNora [17]

Answer:

There are 20 ducklings.

Step-by-step explanation:

For every group of 6 ducks, 5 would be ducklings.

24 / 6 = 4

There are 4 groups of ducks.

5 * 4 = 20

4 0
3 years ago
24% students in a clan were absent in a day .If 38 students were present ,what is the total strength in the clan
Lemur [1.5K]

Answer:

50 students

Step-by-step explanation:

24% students in a clan were absent in a day .

Hence, the Percentage of students present is calculated as:.

= 100 % - 24 %

= 76%

From the question, we know that:

If 38 students were present ,what is the total strength in the clan

The total strength of the clan = Total number of students. This is calculated as:

76% × x = 38 students.

76/100 × x = 38

76x /100 = 38

Cross Multiply

76x = 38 × 100

x = 3800/76

x = 50 students

5 0
3 years ago
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