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Margarita [4]
3 years ago
10

Convert the fractions to decimals.

Mathematics
1 answer:
AnnZ [28]3 years ago
5 0
<span>3/20: 0.15
7/50: 0.14
9/25: 0.36
4/15: 0.266667
1/9: 0.111111
9/40: 0.225
5/16: 0.3125
7/9: 0.777778
13/20: 0.65
37/50: 0.74
11/30: 0.366667
19/40: </span>0.475
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2. A rectangular prism has e flat surfaces . 3, A cone h as -flat surface. A cube has 요 flat surfaces.
alisha [4.7K]
All correct except that
cube has 6 flat surfaces, it's like a rectagular prism, but special
6 0
3 years ago
HELP ASAP THIS IS SOMETHING DUE IN LESS THAN AN HOUR AND I HAVE OTHER PROBLEMS TO DO
saw5 [17]

Answer:

30 degrees

Step-by-step explanation:

Let Angle ABC be 2x, Angle EBC be 5x

angle \: dbc = 90 - 2x \\ angle \: dbc \:  + angle \: ebc = 180 \\ 90 - 2x + 5x = 180 \\ 3x = 90 \\ x = 30 \\  \\ angle \: dbc = 90 - 60 \\   = 30

5 0
3 years ago
Find all solutions to the equation in the interval [0, 2īt).<br> 4) sin 2x = -sin x
Sonbull [250]

Answer:

x={0, 2pi/3, pi, 4pi/3}

Step-by-step explanation:

First, move sin x by adding sin x to both sides. sin 2x+ sin x = 0. Next using the double angle identity, sin 2x=2(sin x)(cos x), so 2(sin x)(cos x)+sinx=0. Factoring, sin x(2cos x +1)=0. Solving, sin x=0 and 2cos x +1 = 0, or cos x = -1/2.

sin x = 0. Using the unit circle, sin x=0 when x=0 and x=pi.

cosx=-1/2. Using the unit circle, cos x= -1/2 when x=2pi/3 and x=4pi/3.

8 0
3 years ago
Find the area between the graph of the function and the x-axis over the given interval, if possible.
vodomira [7]

Answer:

A= -\frac{5}{-1} - \lim_{x\to\infty} \frac{5}{x-2} = 5-0 = 5

So then the integral converges and the area below the curve and the x axis would be 5.

Step-by-step explanation:

In order to calculate the area between the function and the x axis we need to solve the following integral:

A = \int_{-\infty}^1 \frac{5}{(x-2)^2}

For this case we can use the following substitution u = x-2 and we have dx = du

A = \int_{a}^b \frac{5}{u^2} du = 5\int_{a}^b u^{-2}du

And if we solve the integral we got:

A= -\frac{5}{u} \Big|_a^b

And we can rewrite the expression again in terms of x and we got:

A = -\frac{5}{x-2} \Big|_{-\infty}^1

And we can solve this using the fundamental theorem of calculus like this:

A= -\frac{5}{-1} - \lim_{x\to\infty} \frac{5}{x-2} = 5-0 = 5

So then the integral converges and the area below the curve and the x axis would be 5.

7 0
3 years ago
Please help!!!!!!!!!!
Sergeu [11.5K]
1, 3, and 5 would be my best guesses but I’m not 100 percent sure
7 0
2 years ago
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