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2 years ago

Consider the balanced equation below.

Chemistry

2 answers:

Alexus [3.1K]2 years ago

5 0

Answer : The mole ratios of Hydrazine to Hydrogen peroxide is 1 : 2 and

the mole ratios of Hydrazine to water is 1 : 4.

Explanation :

The balanced chemical equation is,

$N_{2}H_{4}+2H_{2}O_{2}\rightarrow N_{2}+4H_{2}O$

According to the given reaction,

1 mole of Hydrazine react with the 2 moles of Hydrogen peroxide.

Therefore, the mole ratios of Hydrazine to Hydrogen peroxide is 1 : 2

And in case of Hydrazine and water,

1 mole of Hydrazine gives 4 moles of water.

Therefore, the mole ratios of Hydrazine to water is 1 : 4

Tema [17]2 years ago

4 0

The mole ratio of Hydrazine to hydrogen peroxide is 1:2 and the mole ratio of Hydrazine to water is 1:4

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Cellulose could provide an abundant and cheap form of glucose for humans. Why is cellulose not a source of nutrients for humans?

mojhsa [17]

Answer:

Option (c).

Explanation:

Cellulose is one of the most important carbohydrate of the plant that provide structural framework to the plant cells. Cellulose is made of the monomer of the glucose that are linked through the beta glycosidic linkages.

Although cellulose contains large number of glucose but it cannot be used as the nutrient source for humans. Humans and other vertebrates lacks the enzyme cellulase that is required for the digestion of cellulose. Cellulose cannot be broken down in the human body.

Thus, the correct answer is option (c).

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3 years ago

Fill in the blank:

Roman55 [17]

Answer:

Weathering, Erosion

Explanation:

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Hope this helps

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7 0

2 years ago

Read 2 more answers

If the temperature of the water were 0°C and the pressure was above 760 mm Hg, what phase would the water be in?

viva [34]

I would say the answer is gas.

4 0

1 year ago

Increasing order of unsaturation

Basile [38]

Whats the question? Im not sure what your asking

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2 years ago

A diver has a lung capacity of 2.4 L when the pressure is 0.8 atm. What is the volume of the diver’s lungs when the pressure cha

tangare [24]

Answer:

The final volume is 1.6 L.

Explanation:

It is given that,

A diver has a lung capacity of 2.4 L when the pressure is 0.8 atm. We need to find the volume of the diver’s lungs when the pressure changes to 1.2 atm. Let V₂ is volume.

It is based on Boyle's law. According to this law,

$PV=K$

K is constant

$P_1V_1=P_2V_2$

$V_2=\dfrac{P_1V_1}{P_2}\\\\V_2=\dfrac{0.8\times 2.4}{1.2}\\\\V_2=1.6\ L$

So, the final volume is 1.6 L.

7 0

2 years ago