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Arisa [49]
3 years ago
10

How many atoms of lodine(I) are in 0.156 grams of I?

Chemistry
1 answer:
CaHeK987 [17]3 years ago
4 0

Answer: iodine 131 iodine 132 isotopes

Explanation:

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SiO2 + 4HF = SiF4 + 2H2O, what mass of HF is necessary to produce 12.91g of the SiF4?
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7 0
2 years ago
What is the density of 10.002 g of water at 20c in the units of g/mL?
Elena-2011 [213]

Density of 10.002g of water at 20°C in g/mL = 0.998 g/mL

Given that:

density of water at 20°C = 0.9982 g/mL

 Density = mass / volume ---- ( 1 )

Where :  mass = 10.002 g

               Volume = ?

               Density = 0.9982 g/mL

∴ Volume = 10.002 / 0.9982   = 10.02 mL

<u>back to equation ( 1 ) </u>

Density = 10.002 / 10.02 = 0.9982 g/mL ≈ 0.998 g/mL

Therefore the density of 10.002 g of water at 20°C in the units of g/mL is 0.998 g/mL

Learn more : brainly.com/question/10111575

7 0
2 years ago
In the quantum theory, the magnetic orbital momentum quantum number is most directly associated with which property of orbitals?
kolezko [41]

Answer: In the quantum theory, the magnetic orbital momentum quantum number is most directly associated with orientation of orbitals

In the quantum theory, angular orbital momentum quantum number is most directly associated with shape of orbitals.

Explanation:

Principle Quantum Number : It describes the size of the orbital and the energy level. It is represented by n. Where, n = 1,2,3,4....

Angular orbital momentum quantum number or Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

Magnetic Quantum Number : It describes the orientation of the orbitals. It is represented as m_l. The value of this quantum number ranges from (-l\text{ to }+l). When l = 2, the value of m_l will be -2, -1, 0, +1, +2.

Spin Quantum number : It describes the direction of electron spin. This is represented as m_s The value of this is +\frac{1}{2} for upward spin and -\frac{1}{2} for downward spin.

8 0
2 years ago
Uranium has three common isotopes: U-238 (99.2745%), U-235 (0.7200%), U-234 (0.0055%). Calculate the average atomic mass of uran
leonid [27]

Answer:

237.98

Explanation:

U-238 (99.2745%), U-235 (0.7200%), U-234 (0.0055%).

<em>Multiply mass with percentage of abundance</em>

238 × 99.2745 = <u>23627.331 %</u>

235 × 0.72 = <u>169.2 %</u>

234 × 0.0055 = <u>1.287 %</u>

<em>Add all the percentages.</em>

23627.331 + 169.2 + 1.287 = 237978.818 %

As a whole number it is = \frac{237978.818}{100}

Average atomic mass of Uranium= <u>237.98</u><em> </em>[rounded to 2 decimal places]

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2 years ago
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Answer:

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