How many atoms of lodine(I) are in 0.156 grams of I?

How should an ethical scientist response if an experiment does not confirm a hypothesis? Question 2 options:Revise the hypothesi

miv72 [106K]

For the first question, its revise the hypothesis and develop a new experiment to test it

For the second question, the fertilizer independent variable

7 0

3 years ago

g A radioactive isotope of mercury, 197Hg, decays to gold, 197Au, with a disintegration constant of 0.0108hrs.-1. What % of the

weqwewe [10]

Answer:

7.49% of Mercury

Explanation:

Let N₀ represent the original amount.

Let N represent the amount after 10 days.

From the question given above, the following data were obtained:

Rate of disintegration (K) = 0.0108 h¯¹

Time (t) = 10 days

Percentage of Mercury remaining =?

Next, we shall convert 10 days to hours. This can be obtained as follow:

1 day = 24 h

Therefore,

10 days = 10 day × 24 h / 1 day

10 days = 240 h

Thus, 10 days is equivalent to 240 h.

Finally, we shall determine the percentage of Mercury remaining as follow:

Rate of disintegration (K) = 0.0108 h¯¹

Time (t) = 10 days

Percentage of Mercury remaining =?

Log (N₀/N) = kt /2.303

Log (N₀/N) = 0.0108 × 240 /2.303

Log (N₀/N) = 2.592 / 2.303

Log (N₀/N) = 1.1255

Take the anti log of 1.1255

N₀/N = anti log 1.1255

N₀/N = 13.3506

Invert the above expression

N/N₀ = 1/13.3506

N/N₀ = 0.0749

Multiply by 100 to express in percent.

N/N₀ = 0.0749 × 100

N/N₀ = 7.49%

Thus, 7.49% of Mercury will be remaining after 10 days

5 0

2 years ago

Write the net ionic equation for the reaction of aqueous solutions of ammonium chloride and iron(III) hydroxide.

vagabundo [1.1K]

Answer:

$Fe(OH)_3(s)\rightarrow Fe^{3+}(aq)+3OH^-(aq)$

Explanation:

Hello.

In this case, for the reaction between aqueous solutions of ammonium chloride and iron (III) hydroxide, we have the following complete molecular reaction:

$3NH_4Cl(aq)+Fe(OH)_3(s)\rightarrow 3NH_4OH+FeCl_3$

And the full ionic equation, taking into account that the iron (III) hydroxide cannot be dissolved as it is insoluble in water:

$3NH_4^+(aq)+3Cl^-(aq)+Fe(OH)_3(s)\rightarrow 3NH_4^+(aq)+3OH^-(aq)+Fe^{3+}(aq)+3Cl^-(aq)$

Finally, the net ionic equation, considering that spectator ions are NH₄⁺, Cl⁻ as they are both the left and right side, therefore, the net ionic equation is:

$Fe(OH)_3(s)\rightarrow Fe^{3+}(aq)+3OH^-(aq)$

Best regards.

8 0

2 years ago

The extraction of pure copper is expensive. Give one reason why

goblinko [34]

Because it requires lots of electricity to turn it into an aqueous solution so that electrolysis can be performed on it.

3 0

3 years ago

Read 2 more answers

guys please help me WILL MARK BARINLIEST If you have 5.7 x 10^24 molecules of O2 at STP, how many liters of O2 do you have? must

zmey [24]

Answer:

212.8 dm^3 or L

Explanation:

1 mole of any sub=6.02×10^23 molecules

X mole of O2=5.7×10^24 molecules

X mole=5.7×10^24/6.02×10^23

=9.5 mole

1 mole of any gas at stp=22.4 dm^3

Therefore, 9.5 mole of O2 will be 22.4×9.5

=212.8 dm^3

5 0

2 years ago