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Arisa [49]
3 years ago
10

How many atoms of lodine(I) are in 0.156 grams of I?

Chemistry
1 answer:
CaHeK987 [17]3 years ago
4 0

Answer: iodine 131 iodine 132 isotopes

Explanation:

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Eyes, nose, mouth would each be an example of a(n)
Masja [62]

Answer:

I think it is Organ

Explanation:

5 0
3 years ago
Planets in our solar system revolve around the Sun because
yulyashka [42]
Planets revolve around the sun because of gravity. When the planets were made, the sun's gravity was strong enough so that the planets continued to stay around the sun and orbit.
4 0
4 years ago
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If we reverse the reaction to read Z + Q → X + Y, the +ΔH would be a -ΔH. Does this indicate that heat is given off or absorbed
grin007 [14]

Answer:

Reactants.  

Step-by-step explanation:

The equation for the reverse reaction is

Z + Q ⟶ X + Y; ΔH < 0

A negative ΔH indicates that the energy has been given off.

The products X + Y are at a <em>lower energy level</em> than the reactants Z + Q, and the excess energy has been <em>transferred to the surroundings</em>.

8 0
4 years ago
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If you have 3.48 x 1023 formula units of Lead (II) Permanganate, what is its mass?
Tanya [424]

Answer:

\large \boxed{\text{257 g}}

Explanation:

We can convert the formula units to moles and then use the molar mass to find the mass.

1. Moles of Pb(MnO₄)₂

n = 3.48 \times 10^{23}\text{ formula units} \times \dfrac{\text{1 mol}}{6.022 \times 10^{23}\text{ formula units}} = \text{0.5779 mol}

 

2. Mass of Pb(MnO₄)₂

\text{Mass} = \text{0.5779 mol} \times \dfrac{\text{445.07 g}}{\text{1 mol u}} = \text{257 g}\\\\\text{The mass of lead(II) permanganate is $\large \boxed{\textbf{257 g}}$}

4 0
4 years ago
If 18.0 mL of 0.800 M HCl solution are needed to neutralize 5.00 mL of a household ammonia solution, what is the molar concentra
k0ka [10]

<em>Answer:</em>

  • The molarity of ammonia will be 2.88 M.

<em>Chemical equation</em>

                                      HCl +  NH3 ------> NH4Cl

First of calculate the moles of HCl

mole of HCl = Molarity × Vol (L)

mole of HCl = 0.800× 0.018 = 0.014 mole

As the in balance chemical, moles of HCl and NH3 areequal

so

                        moles of NH3= 0.014

                       Molarity of NH3 = moles ÷ V(L) = 0.014/0.005 =  2.88 M

<em>Result</em>:

  • The molarity of ammonia will be 2.88 M.
3 0
3 years ago
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