You have to make 500 mL of a 1.50 M BaCl2. You have 2.0 M barium chloride solution available. Determine how to make the needed d
1 answer:
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Answer:
A)Mass of gallium plated out is 0.3440 grams
B) For 0.67 hours current of 5.79 A must to be applied to plate out 8.70 g of tin.
Explanation:
To calculate the total charge, we use the equation:
where,
C = Charge
I = Current in time t (seconds)
To calculate the moles of electrons, we use the equation:
where,
F = Faraday's constant = 96500
A) The equation for the deposition of Ga(s) from Ga(III) solution follows:
I = 0.790 A, t = 30.0 min = 1800 seconds
Moles of electron transferred:
Now, to calculate the moles of gallium, we use the equation:
n = number of electrons transferred = 3
Mass of 0.004913 moles of gallium = 0.004913 mol × 70 g/mol=0.3440 g
B) The equation for the deposition of Sn(s) from Sn(II) solution follows:
Moles of tin =
n = number of electrons transferred = 2
Moles of electron =
Charge transferred during time t :
Current applied for t time = I = 5.79 A
For 0.67 hours current of 5.79 A must to be applied to plate out 8.70 g of tin.