The number of defective modems in the inventory is 20%⋅ 30 + 8%⋅ 50 = 10 (out of 80).
Note that the number of defectives in the inventory is fixed, i.e., we are not told that there
is 1
8 probability that a modem in the inventory is defective, but rather that exactly 1
8
of
all modems are defective. The probability that exactly two modems in a random sample
of five are defective is = 0.102
Answer:
I Think it is A
Step-by-step explanation:
It is a because 9×7=63
X = small van capacity, y = larger van capacity
y = x + 6
2x + y = 57
now we sub in x + 6 for y
2x + x + 6 = 57
3x + 6 = 57
3x = 57 - 6
3x = 51
x = 51/3
x = 17
y = x + 6
y = 17 + 6
y = 23
small van (x) has 17 seats and large van (y) has 23 seats