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slava [35]
2 years ago
9

←

Mathematics
1 answer:
maw [93]2 years ago
3 0

The equation that is represented by the graph below is y = e^x - 4.

<h3>How to illustrate the graph?</h3>

From the graph, it can be seen that the only exponential function n to hat intercept the function at equal to 3 is y = e^x - 4.

Let's equate y to 0.

y = e^x - 4.

e^x - 4 = 0

e^x = 4

In(e^x) = In(4)

x = 1.386

The x intercept is located at (1.386, 0).

In conclusion, the correct option is D.

Learn more about graph on:

brainly.com/question/12886416

#SPJ1

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98 x 63 – 32 x 69 =
Dahasolnce [82]

Answer:

3966

Step-by-step explanation:

Use order of operations to solve this problem:

  • Parentheses
  • Exponents
  • Multiply (Left to right)
  • Divide (Left to right)
  • Addition
  • Subraction

In your case, there are no parentheses or exponents, so we can skip right the the multiply and divide step. The first multiplication is 98*63=6174. The next step is to do 32*69=2208. Then you minus 6174-2208=3966.

Hope this helps!

7 0
2 years ago
What is the value of x
makkiz [27]

Answer:

x = 4 root square 3

Step-by-step explanation:

sin60° = x/8

x = 8×sin60° = 4 root square 3

7 0
3 years ago
If 8p = 3p + 25, what is the value of p? Select the best answer from the choices provided. p = 4 p = 5 p = 6 p = 8
kiruha [24]
<span>8p = 3p + 25 
Subtract 3p from both sides: 5p = 25 Divide both sides by 5: '
p = 5</span>
4 0
3 years ago
Read 2 more answers
. Imagine a game of 3 players where exactly one player wins in the end and all players have equal chances of being the winner. T
lbvjy [14]

Answer:

5/9

Step-by-step explanation:

Number of players = 3

number of times game is repeated = 4

P( any person wins a game ) = 1/3

P ( any person does not win a game ) = 1 - 1/3 = 2/3

P ( any person wins no game in 4 attempts ) = ( 2/3 )^4 = 16/81

<em>Note : each player has equal chance of winning </em>

<u>Find the probability that there is at least one person who wins no games </u>

lets represent the probability of each player not wining a game with alphabet A

A1 = player 1 wins no game

A2 = player 2 wins no game

A3 = players 3 wins no game

Applying the inclusion-exclusion formula

<em>P( A1 ∪ A2 U A3 )</em><em> = P(A1 ) + P(A2) + P(A3) - P( A1 ∩ A2 ) - P( A2 ∩ A3 ) - P( A1            ∩ A3 )  + P( A1 ∩ A2 ∩ A3 ) </em>

where

P( A1 ∩ A2 ) = P( A1 wins all games )

P ( A1 wins all games in 4 attempts ) = ( 1/3 )^4 = 1/81

P( A1 ∩ A2 ∩ A3 ) = P ( no players wins any game in 4 attempts ) = 0

Hence

P( A1 ∪ A2 U A3 ) = 16/81 + 16/81 + 16/81 - 1/81 - 1/81 - 1/81 - 0 = 5/9

6 0
2 years ago
THIS IS VERY IMPORTANT!
tatyana61 [14]

Answer:

I think Leslie Is 20

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
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