Answer:
x = -3/2 ± i(√11)/2
Step-by-step explanation:
The quadratic formula can be used directly, but I find it convenient to divide by 14 first:
x^2 +3x +5 = 0
The solution to ...
ax^2 +bx +c = 0
is given by the formula ...
x = (-b ±√(b^2 -4ac))/(2a)
Here, we have a=1, b=3, c=5, so the formula gives the solutions ...
x = (-3 ±√(3^2 -4·1·5))/(2·1) = -3/2 ± i(√11)/2 . . . . . solutions are complex
