Solve 14x^2 + 42x + 70 = 0

Mathematics

1 answer:

Dvinal [7]3 years ago

6 0

Answer:

x = -3/2 ± i(√11)/2

Step-by-step explanation:

The quadratic formula can be used directly, but I find it convenient to divide by 14 first:

x^2 +3x +5 = 0

The solution to ...

ax^2 +bx +c = 0

is given by the formula ...

x = (-b ±√(b^2 -4ac))/(2a)

Here, we have a=1, b=3, c=5, so the formula gives the solutions ...

x = (-3 ±√(3^2 -4·1·5))/(2·1) = -3/2 ± i(√11)/2 . . . . . solutions are complex

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