The perimeter of a circular park is 880 m. Find the area of the park.

Find the volume of the following compound shape.

Bess [88]

<h3>Given:</h3>

Cone
Cylinder

<h3>Volume of the cone:</h3>

$v = \frac{1}{3} \pi {r}^{2} h$

$v = \frac{1}{3} \times \pi \times {10}^{2} \times 10$

$v = 1047.20 \: {cm}^{3}$

<h3>Volume of the cylinder:</h3>

$v = \pi {r}^{2} h$

$v = \pi \times {10}^{2} \times 10$

$v = 3141.59 \: {cm}^{3}$

<h3>Total volume:</h3>

$v = 1047.20 + 3141.59$

$v = 4188.79 \: {cm}^{3}$

Hence, the volume of the given cone shape is 4188.79 cubic centimeters.

5 0

1 year ago

Read 2 more answers

Evaluate |-a^2|, given a = 5, b = -3, and c = -2.

geniusboy [140]

The sunset is 25. how this helps!

7 0

2 years ago

Read 2 more answers

Can someone explain this? (This is algebra 1)

12345 [234]

Answer:

x=12

Triangle abc and Def are congruent but different sizes. The original triangle has side values of 2, 6 and 5. Then the shape is dilated by an unknown factor, giving it the side lengths of 4, x, and 10. Looking at the increase in side lengths we see that theres an increase of 2 to 4, or multiplying by 2 and an increase from 5 to 10, or multiplying by to. So now that we know there was a dilation of 2, we multiply 6 by 2 to find 12

5 0

2 years ago

Totsakan school is selling tickets to a choral performance on the first day of ticket sales the school sold 10 senior tickets an

ohaa [14]

Given :

On the first day of ticket sales the school sold 10 senior tickets and 1 child ticket for a total of $85 .

The school took in $75 on the second day by selling 5 senior citizens tickets and 7 child tickets.

To Find :

The price of a senior ticket and the price of a child ticket.

Solution :

Let, price of senior ticket and child ticket is x and y respectively.

Mathematical equation of condition 1 :

10x + y = 85 ...1)

Mathematical equation of condition 2 :

5x + 7y = 75 ...2)

Solving equation 1 and 2, we get :

2(2) - (1) :

2( 5x + 7y - 75 ) - ( 10x +y - 85 ) = 0

10x + 14y - 150 - 10x - y + 85 = 0

13y = 65

y = 5

10x - 5 = 85

x = 8

Therefore, price of a senior ticket and the price of a child ticket $8 and $5.

Hence, this is the required solution.

5 0

3 years ago

A sample of a radioactive substance decayed to 97% of its original amount after a year. (Round your answers to two decimal place

Andrej [43]

Answer:

a) The half life of the substance is 22.76 years.

b) 5.34 years for the sample to decay to 85% of its original amount

Step-by-step explanation:

The amount of the radioactive substance after t years is modeled by the following equation:

$P(t) = P(0)(1-r)^{t}$

In which P(0) is the initial amount and r is the decay rate.

A sample of a radioactive substance decayed to 97% of its original amount after a year.

This means that:

$P(1) = 0.97P(0)$

Then

$P(t) = P(0)(1-r)^{t}$

$0.97P(0) = P(0)(1-r)^{0}$

$1 - r = 0.97$

So

$P(t) = P(0)(0.97t)^{t}$

(a) What is the half-life of the substance?

This is t for which P(t) = 0.5P(0). So

$P(t) = P(0)(0.97t)^{t}$

$0.5P(0) = P(0)(0.97t)^{t}$

$(0.97)^{t} = 0.5$

$\log{(0.97)^{t}} = \log{0.5}$

$t\log{0.97} = \log{0.5}$

$t = \frac{\log{0.5}}{\log{0.97}}$

$t = 22.76$

The half life of the substance is 22.76 years.

(b) How long would it take the sample to decay to 85% of its original amount?

This is t for which P(t) = 0.85P(0). So

$P(t) = P(0)(0.97t)^{t}$

$0.85P(0) = P(0)(0.97t)^{t}$

$(0.97)^{t} = 0.85$

$\log{(0.97)^{t}} = \log{0.85}$

$t\log{0.97} = \log{0.85}$

$t = \frac{\log{0.85}}{\log{0.97}}$

$t = 5.34$

5.34 years for the sample to decay to 85% of its original amount

8 0

3 years ago

The perimeter of a circular park is 880 m. Find the area of the park.​

The perimeter of a circular park is 880 m. Find the area of the park.