<span>D. 20 + 2âš10 units
To solve this, you simply need to calculate the length of each side of the triangle with the vertexes of A(3,4), B(-5,-2), and C(5,-2). The length of each side is simply calculated using the pythagoras theorem. Note that it doesn't matter what order you do the subtraction. The absolute value will be the same and if it happens to be negative, not a problem since it will become positive once you square the values.
So the length of side AB is
sqrt((3-(-5))^2 + (4-(-2))^2) = sqrt(8^2 + 6^2) = sqrt(64 + 36) = sqrt(100) = 10.
The length of side BC is
sqrt((-5 - 5)^2 + (-2 - (-2))^2) = sqrt(-10^2 + 0^2) = sqrt(100+0) = sqrt(100) = 10.
And finally, the length of side AC is
sqrt((3-5)^2 + (4-(-2))^2) = sqrt(-2^2 + 6^2) = sqrt(4+36) = sqrt(40)
= 2 * sqrt(10)
Finally, add all the lengths together.
10 + 10 + 2âš10 = 20 + 2âš10</span>
Answer:
1/2
Step-by-step explanation:
So do this, think of an equilateral triangle. A 30-60-90 triangle is just half of an equilateral triangle. If the original side length was x, then the hypotenuse is x, one leg is x/2, and the third, by Pythagorean theorem, is x sqrt3
Sin is opposite over hypotenuse, so we have (x/2)/x = 1/2
Answer:
The correct line is the third one, x must be less than 16.
Step-by-step explanation:
Give me a brainliest.
Answer:
To graph a rational function, you find the asymptotes and the intercepts, plot a few points, and then ... graphing showing vertical asymptote at x = 1 ... Next, I'll find any x- or y- intercepts.
Answer:
12/13
Step-by-step explanation:
m=(-6-6)/(-7-6)=-12/-13=12/13
