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Evgesh-ka [11]
3 years ago
11

Plz help me answer the whole page

Mathematics
1 answer:
dangina [55]3 years ago
8 0
#2 5.88 #3 6.510 #4 7.578 #5 9.835 #6 11.910 #7 3.72
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the area is 6

Step-by-step explanation:

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3. Why do cube roots of negative numbers exist in the set of real numbers,
Paladinen [302]

Answer:

  C. The square root of a number, positive or negative, is always positive. However, the cube of a negative number is negative.

Step-by-step explanation:

Of the choices offered, the one shown above is the only one that remotely makes any sense. Its description of square roots is erroneous, however.

The square root of a number n is the solution to the equation ...

  x² = n

The function f(x) = x² has a range that only includes non-negative numbers, so the square root of a negative number does not exist. (Your answer choice says it is positive. It is actually non-existent among real numbers.)

On the other hand, the cube root of a number n is the solution to the equation ...

  x³ = n

Since f(x) = x³ has a range that includes all real numbers, the cube root of n exists for all real numbers. (It is negative for negative values of n.)

_____

<em>Comment on answer wording</em>

The answer wording would be correct if the word "root" were left out.

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29. Which property justifies the statement below?
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d I think is right sorry If it's not

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