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the total weight of 6 pieces of butter and a bag of sugar is 3.8 Ib. if the weight of the bag of sugar is 1.4 Ib, what is the we

baherus [9]

0.4 lbs each.

<h3>Further explanation</h3>

<u>Given: </u>

The total weight of 6 pieces of butter and a bag of sugar is 3.8 Ib.
The weight of the bag of sugar is 1.4 Ib

<u>Question: </u>

What is the weight of each piece of butter?

<u>The Process: </u>

The two steps for obtaining the weight of each piece of butter are as follows:

<u>Step-1:</u> the total amount of butter is the total bag of butter and sugar subtracted by the weight of the bag of sugar.

$\boxed{ \ 3.8 \ lbs - 1.4 \ lbs = 2.4 \ lbs \ }$

<u>Step-2:</u> the total amount of butter divided by the number of pieces of butter is the the weight of each piece of butter.

$\boxed{ \ 2.4 \ lbs \div 6 \ pieces = \boxed{ \ 0.4 \ lbs/piece \ } \ }$

Let's also consider the following quick steps.

<u>Quick steps: </u>

$\boxed{ \ \frac{(3.8 - 1.4) \ lbs}{6 \ pieces} = \boxed{ \ 0.4 \ lbs/piece \ } \ }$

Therefore, the weight of each piece of butter is 0.4 lbs.

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Keyword: the total weight, 6 pieces of butter, a bag of sugar is 3.8 Ib, if the weight of the bag of sugar is 1.4 Ib, each piece, subtracted, divide

5 0

2 years ago

Read 2 more answers

WHOEVER ANSWERS FIRST OR ANSWERS THE BEST WILL GET BRAINLIEST WORTH 40 POINTS!!!!!!!!!!!!!!

Irina18 [472]

Answer:

12+12+28+30+18=100

Step-by-step explanation:

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8 0

2 years ago

What is the maximum number of turns for the graph of f(x)=x^4+3x^2?

Stels [109]

Answer:

The turns of a graph is represented by the number of maximum or minimum that the function has.

If we differenciate f(x) we get:

f'(x)=4x^3+6x

f'(x)=2x(2x^2 + 3)

Therefore f'(x) =0, when x=0. Given that negative roots are not defined.

Therefore, the number of turns will be given by the number of solutions of f'(x) which is 1.

Attached you find the graph of the function which confirms the number of turns.

If the function had other solutions, the maximum number of turns it could have is 3! because f'(x) is a third degree polynomial, therefore it can't have more than 3 solutions!