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SOVA2 [1]
3 years ago
9

(-2h3n2)(-5h2n2) How

Mathematics
1 answer:
IRINA_888 [86]3 years ago
3 0

Answer: 9h x 8n^2

we rearrange this underneath the question (-5h-2h) (2nx3n)(2+2) or if 2^2 see explanation. It must therefore be 7h6n4

Step-by-step explanation:

if its ^2 )(power2) then the second reasonable answer is (7h-2h)(2n^2 x 2n^2)=9h x 4n^2 x4n^2 =9h 8n^2 or 17hn^2 but i leave as 9h 8n^2

You can expand only if multiplying 9hx4 for example but not combine the letters. The questions that ask you to mix are much different to this. but if you want to add them 9h+8n^2 =17hn^2

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Which table represents a function? A 2-column table with 4 rows. The first column is labeled x with entries negative 3, 0, negat
tangare [24]

Answer:

This is a many-to-one function as the value of y = -1 corresponds to two values of x:

\begin{array}{|c|c|}\cline{1-2} x & y\\\cline{1-2} -3 & -1\\\cline{1-2} 0 & 0\\\cline{1-2} -2 & -1\\\cline{1-2} 8 & 1\\\cline{1-2}\end{array}

Step-by-step explanation:

<u>Function</u>

A special relationship where each input (x-value) has a single output (y-value).

A function is <u>one-to-one</u> if each value in the range (y-values) corresponds to exactly one value in the domain (x-values).

A function is <u>many-to-one</u> if some values in the range (y-values) correspond to more than one (many) value in the domain (x-values).

This is a many-to-one function as the value of y = -1 corresponds to two values of x:

\begin{array}{|c|c|}\cline{1-2} x & y\\\cline{1-2} -3 & -1\\\cline{1-2} 0 & 0\\\cline{1-2} -2 & -1\\\cline{1-2} 8 & 1\\\cline{1-2}\end{array}

This is not a function as the value of x = -5 corresponds to two values of y:

\begin{array}{|c|c|}\cline{1-2} x & y\\\cline{1-2} -5 & -5\\\cline{1-2} 0 & 0\\\cline{1-2} -5 & 5\\\cline{1-2} 6 & -6\\\cline{1-2}\end{array}

This is not a function as the value of x = -2 corresponds to two values of y:

\begin{array}{|c|c|}\cline{1-2} x & y\\\cline{1-2} -4 & 8\\\cline{1-2} -2 & 2\\\cline{1-2} -2 & 4\\\cline{1-2} 0 & 2\\\cline{1-2}\end{array}

This is not a function as the value of x = -4 corresponds to two values of y:

\begin{array}{|c|c|}\cline{1-2} x & y\\\cline{1-2} -4 & 2\\\cline{1-2} 3 & 5\\\cline{1-2} 1 & 3\\\cline{1-2} -4 & 0\\\cline{1-2}\end{array}

8 0
2 years ago
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adoni [48]

Answer:

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8 0
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Answer:

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Step-by-step explanation:

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