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Murrr4er [49]
3 years ago
12

What is the range of the function y= 2e^x -1 ?

Mathematics
2 answers:
PtichkaEL [24]3 years ago
6 0

The range is all real number greater than - 1

Nesterboy [21]3 years ago
5 0

Answer:

All real numbers greater than -1

Step-by-step explanation:

We have to find the range of:

  y=2e^x-1

We know that e^x lies in (0,∞)

Hence, 2e^x lies in (0,∞)

Hence, 2e^x-1 lies in (-1,∞)

Hence, the range of y=2e^x-1 is:

All real numbers greater than -1

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First, you set your problem up like this: 

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3 years ago
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