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2 years ago

The frequency of a vibrating guitar

Mathematics

2 answers:

SOVA2 [1]2 years ago

6 0

Answer:

First of all yourself

Step-by-step explanation:

PolarNik [594]2 years ago

3 0

Answer:

5.59 per seconds

Step-by-step explanation:

F is inversely proportional to L i.e

F & 1/L

F = K/L

FL = K

But F = 4.3, L = 0.65

K = FL = 4.3 x 0.65

K = 2.795

Now, we can find F when L = 0.5 by doing the following:

F = K/L

F = 2.795/0.5

F = 5.59 per seconds

You might be interested in

Which pair of angles shares ray A.F as a common side? DAF and DAB EAF and CAE BAF and EAD BAF and FAD

shtirl [24]

Answer:

BAF and FAD

Step-by-step explanation:

In order for an angle to have A.F as a side, it must have the letters A.F or FA in its name.

In DAF, the angle is made of rays AD and A.F. In DAB, the angle is made up of rays AD and AB. This is not the correct pair.

In EAF, the angle is made of rays AE and A.F. In CAE, the angle is made up of rays AC and AE. This is not the correct pair.

In BAF, the angle is made of rays AB and A.F. In EAD, the angle is made up of rays AE and AD. This is not the correct pair.

In BAF, the angle is made up of rays AB and A.F. In FAD, the angle is made up of rays A.F and AD. This is the correct pair.

5 0

3 years ago

Read 2 more answers

If DA = 6 and MD = 4, what is the length of DK?

Leto [7]

Answer:

DK = 9

Step-by-step explanation:

In triangle AMD,

h² = p² + b²

or, h² = 6² + 4²

or, h²= 36 + 16

so, h² = 52

so, AM² = 52

Take x as reference angle,

cos²x = 16/52

Now,

In triangle, AMK,

Taking x as reference angle,

cos²x = b²/h²

cos²x = AM²/MK²

or, cos²x = 52/MK²

Now,

cos²x = 16/52 = 52/MK²

or,

16/52 = 52/MK²

or, 16MK² = 2704

or, MK² = 2704/16

or, MK² = 169

so, MK = 13

Now,

DK = MK - MD

or, DK = 13 - 4

so, DK = 9

3 0

2 years ago

Find two unit vectors orthogonal to both given vectors. i j k, 4i k

Maurinko [17]

The cross product of two vectors gives a third vector $\mathbf v$ that is orthogonal to the first two.

$\mathbf v=(\vec i+\vec j+\vec k)\times(4\,\vec i+\vec k)=\begin{vmatrix}\vec i&\vec j&\vec k\\1&1&1\\4&0&1\end{vmatrix}=\vec i+3\,\vec j-4\,\vec k$

Normalize this vector by dividing it by its norm:

$\dfrac{\mathbf v}{\|\mathbf v\|}=\dfrac{\vec i+3\,\vec j-4\,\vec k}{\sqrt{1^2+3^2+(-4)^2}}=\dfrac1{\sqrt{26}}(\vec i+3\,\vec j-4\vec k)$

To get another vector orthogonal to the first two, you can just change the sign and use $-\mathbf v$ .