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Amanda [17]
4 years ago
15

16 lakh students in India use khan academy today. The number of users are expected to grow by 50% every year. How many students

in India would be using Khan Academy two years from now ?
Mathematics
1 answer:
trapecia [35]4 years ago
6 0

Answer: 32,00,000

Step-by-step explanation:

We can use the formula

16,00,000 x 0.5 x 2 = 16,00,000

Total no. of students using Khan Academy after 2 years will be:

1600000 + 1600000 = 32,00,000

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What is the difference between linear pair supplementary angle and straight angle?
Ivenika [448]
They both are 180 degrees.

One possible difference is that a straight angle is just a single angle measuring 180 degrees, while a linear pair supplementary angle are pairs of adjacent angles that add up to 180 degrees.
3 0
3 years ago
En la tienda de mascotas "Animalo-T", se desea elevar un elefante de 2,900 kg utilizando una elevadora hidráulica de plato grand
Korvikt [17]

Answer:

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

Step-by-step explanation:

Por el Principio de Pascal se conoce que el esfuerzo experimentado por el elefante es igual a la presión ejercida por el plato pequeño. Es decir:

\frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}} (1)

Donde:

F_{1} - Fuerza experimentada por el elefante, medida en newtons.

F_{2} - Fuerza aplicada sobre el plato pequeño, medida en newtons.

A_{1} - Área del plato grande, medida en metros cuadrados.

A_{2} - Área del plato pequeño, medida en metros cuadrados.

La fuerza aplicada sobre el plato pequeño es:

F_{2} = \left(\frac{A_{2}}{A_{1}} \right)\cdot F_{1}

La fuerza experimentada por el elefante es su propio peso. Por otra parte, el área del plato es directamente proporcional al cuadrado de su diámetro. Es decir:

F_{2} = \left(\frac{D_{2}}{D_{1}} \right)^{2}\cdot m\cdot g (2)

Donde:

D_{1} - Diámetro del plato grande, medido en centímetros.

D_{2} - Diámetro del plato pequeño, medido en centímetros.

m - Masa del elefante, medida en kilogramos.

g - Aceleración gravitacional, medida en metros por segundo cuadrado.

Si sabemos que D_{1} = 0.75\,m, D_{2} = 0.13\,m, m = 2900\,kg y g = 9.807\,\frac{m}{s^{2}}, entonces la fuerza a aplicar al émbolo pequeño es:

F_{2} = \left(\frac{0.13\,m}{0.75\,m} \right)^{2}\cdot (2900\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)

F_{2} = 854.473\,N

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

3 0
3 years ago
5. The daily temperature recorded (in degree F) at a place during a week was as under:
SSSSS [86.1K]

Answer:

29.9 °F

Step-by-step explanation:

The formular for mean is given as;

Mean = Sum of Terms / Number of terms

Number of terms = 6

Sum of terms = 35.5  + 30.8  + 27.3  + 32.1  + 23.8  + 29.9 = 179.4

Mean = 179.4 / 6 = 29.9

4 0
3 years ago
Help asap please!!!! due tonight!!! brainliest for fastest right answer!!! xx​
Serga [27]

Answer:

Step-by-step explanation:

3 0
2 years ago
Solve P= 2B + 2M for B
kykrilka [37]

Answer:

B = P/ 2 − M

Step-by-step explanation:

8 0
3 years ago
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