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Margaret [11]
3 years ago
13

Solve 1/2x + 3 < 4x - 7

Mathematics
1 answer:
Serhud [2]3 years ago
3 0
20/7 if you download the app photo math or go to the website symbalo it really helps with order of operations
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Find the equation of the line that passes through the points ​(1​,12​) and ​(3​,
Anna35 [415]

Answer:

y=-2x+14

Step-by-step explanation:

hope this can help

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3 years ago
This photograph shows US. residents at an internment camp during World War Il Many of these people had been residents of what
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Answer:

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Step-by-step explanation:

4 0
2 years ago
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What is 12x/7 multiplied by 9/8x ?
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108x/56x Hope that helps.
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3 years ago
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Connor is going to see a movie and is taking his 4 kids. Each movie ticket costs $13 and there are an assortment of snacks avail
EleoNora [17]

If Connor buys 3 snacks at 3 dollars each for himself and his 3 children, the net cost (including movie tickets) would be 88 dollars.

If he buys x amount of snacks, his cost will be determined by C=52+3x or C=52+3*x (both are equivalent, but not everyone knows every way to represent multiplication)

Step-by-step explanation:

To find the cost of the snacks:

Cost = Price*NumberOfSnacks, or C=p*n, or C=pn

To find the unit cost of the snack, find the price, the p value, which is 3 dollars.

Then, find the total number of snacks that will be bought. Since each person receives an equal number of snacks, 3 per person, and there are 4 people (himself and his 3 children), we can multiply 3*4 to find the n value, which is now known to be 12.

C=3*12=36. Add to the 13 dollar per person charge for tickets (52 dollars for 4 people), and you get 88 dollars.

To find the cost if he buys x amount of snacks for himself and his 3 children (assumed to be "everyone"), all costs but the n value are to be the same, creating this equation:

C=52+3x

In this context, 52 is the cost of movie tickets, 3 is the cost of the snacks, and x is the total number of snacks bought. C represents total cost.

5 0
2 years ago
Which of the following geometric series converges?
Artist 52 [7]

All three series converge, so the answer is D.

The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.

Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

S_n=a+ar+ar^2+\cdots+ar^{n-2}+ar^{n-1}

Multiply both sides by <em>r</em> :

rS_n=ar+ar^2+ar^3+\cdots+ar^{n-1}+ar^n

Subtract the latter sum from the first, which eliminates all but the first and last terms:

S_n-rS_n=a-ar^n

Solve for S_n:

(1-r)S_n=a(1-r^n)\implies S_n=\dfrac a{1-r}-\dfrac{ar^n}{1-r}

Then as gets arbitrarily large, the term r^n will converge to 0, leaving us with

S=\displaystyle\lim_{n\to\infty}S_n=\frac a{1-r}

So the given series converge to

(I) -243/(1 + 1/9) = -2187/10

(II) -1.1/(1 + 1/10) = -1

(III) 27/(1 + 1/3) = 18

8 0
3 years ago
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