Answer:
12:1/2(3)
Step-by-step explanation: no problem homie
Answer:
- plane: 530 mi/h
- wind: 40 mi/h
Step-by-step explanation:
Let p and w represent the speeds of the plane and the wind. The relation between time, speed, and distance is ...
speed = distance/time
p +w = (2565 mi)/(4.5 h) = 570 mi/h
p -w = (2205 mi)/(4.5 h) = 490 mi/h
Adding these speeds, we get ...
(p +w) +(p -w) = (570) +(490) mi/h
2p = 1060 mi/h
p = 530 mi/h
Then the speed of the wind is ...
w = 570 mi/h -p = (570 -530) mi/h = 40 mi/h
The plane's speed is 530 mi/h; the wind speed is 40 mi/h.
I was working on it until I saw it was only 5 points. Sorry bro
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<u>Answer:</u></h3>
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<u>Solution</u><u>:</u></h3>
In the given question, we have to factorise the equation:
Therefore, by using the middle term splitting method:
- This method is used in equations which are in the form of ax² + bx + c. Here, we split the middle term into two terms which on multiplying gives ac and on adding or subtracting gives bx .
➙ 3c² + 2c -16
➙ 3c² - 6c + 8c - 16
➙ ( 3c² - 6c )+ (8c - 16 )
➙ 3c( c - 2 ) + 8 ( c - 2 )
➙ ( c - 2 ) ( 3c + 8 )
