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3 years ago

What is the inequality using X Solve the inequality

Mathematics

2 answers:

vivado [14]3 years ago

8 0

The inequality should be 4x + 6 > 30
4 times x is 4x, and if anything is greater then smth, you should use > if that number is on the left.
to solve, just do what u would do in algebra, except charging the = into >
4x + 6 > 30
4x > 30 - 6
x > 24/4
x > 6

tatuchka [14]3 years ago

7 0

Answer: <span> x > 6</span> .
_________________________
Explanation:
_________________________

4x + 6 <span> > 30 ; Solve for "x" ;
_________________________

Subtract "6" from both sides of the inequality:
____________________________________
4x + 6 </span>− 6 > 30 − 6 ; to get:
____________________________________
4x > 24 ;
____________________________________
Divide EACH SIDE of the inequality by "4" ; to isolate "x" on one side of the inequality; and to solve the inequality (for "x") ;
__________________________________
4x / 4 > 24 / 4 ; to get:
__________________________________
x > 6 .
__________________________________

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2 years ago

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3 years ago

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Answer:

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Given sin(u)= -7/25 and cos(v) = -4/5, what is the exact value of cos(u-v) if both angles are in quadrant 3

solmaris [256]

Given:

$\sin (u)=-\dfrac{7}{25}$

$\cos (v)=-\dfrac{4}{5}$

To find:

The exact value of cos(u-v) if both angles are in quadrant 3.

Solution:

In 3rd quadrant, cos and sin both trigonometric ratios are negative.

We have,

$\sin (u)=-\dfrac{7}{25}$

$\cos (v)=-\dfrac{4}{5}$

Now,

$\cos (u)=-\sqrt{1-\sin^2 (u)}$

$\cos (u)=-\sqrt{1-(-\dfrac{7}{25})^2}$

$\cos (u)=-\sqrt{1-\dfrac{49}{625}}$

$\cos (u)=-\sqrt{\dfrac{625-49}{625}}$

On further simplification, we get

$\cos (u)=-\sqrt{\dfrac{576}{625}}$

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Similarly,

$\sin (v)=-\sqrt{1-\cos^2 (v)}$

$\sin (v)=-\sqrt{1-(-\dfrac{4}{5})^2}$

$\sin (v)=-\sqrt{1-\dfrac{16}{25}}$

$\sin (v)=-\sqrt{\dfrac{25-16}{25}}$

$\sin (v)=-\sqrt{\dfrac{9}{25}}$

$\sin (v)=-\dfrac{3}{5}$

Now,

$\cos (u-v)=\cos u\cos v+\sin u\sin v$

$\cos (u-v)=\left(-\dfrac{24}{25}\right)\left(-\dfrac{4}{5}\right)+\left(-\dfrac{7}{25}\right)\left(-\dfrac{3}{25}\right)$

$\cos (u-v)=\dfrac{96}{625}+\dfrac{21}{625}$

$\cos (u-v)=\dfrac{1 17}{625}$

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2 years ago

Assuming that one-pint is equal to 473 ml, how many pints can be found in 3 liters?

Svetlanka [38]

Given that 1 pint is equal to 437 ml
and 1000 ml=1 liter
then
1 pint =(437/1000) liters
simplifying we get:
1 pint= 0.437 liters
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3 years ago