The polynomial f(x) leaves a remainder of - 3 and - 7 when divided by (3x - 1) and (x +1) respectively.
1 answer:
Step-by-step explanation:
Here, f(x) is the given polynomial.
By remainder Theorem,
When divided by (3x-1),
f(1/3) = -3........(1)
When divided by (x+1),
f(-1) = -7.........(2)
<em>Another</em><em> </em><em>polynomial</em><em> </em><em>is</em><em> </em><em>3</em><em>x</em><em>²</em><em>+</em><em>2</em><em>x</em><em>-</em><em>1</em>
Solving,
3x²+2x-1
= 3x²+3x-x-1
=3x(x+1)-(x+1)
=(3x-1)(x+1)
So
f(x) = (3x-1)(x+1)Qx + (ax+b)
For f(-1),
-7 = -a+b
b= a-7
For f(1/3),
-3 = a/3+b
or, -3 = a/3+a-7
or, 4×3 = 4a
or a = 3
Also, b = 3-7 =-4
Hence, remainder is (3x-4)
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