Question

After an exceptionally rainy spring, there is no longer a barrier between the populations, and some individuals migrate inland from the coast. Consequently, 20 % of individuals in the new inland population are originally from the coastal population. Calculate the spotted allele frequency for the inland population after migration, q combined . Round the answer to the nearest hundredth.

Answer 1

Answer

After inland population after migration allele frequency is 0.62 or 62%

Explanation:

Given,  

Coastal striped phenotype freq. = 0.22

ss = 0.22

$q_{coastal} \times q_{coastal} = 0.22$

$q_{2 coastal}$= 0.22

Similarly, inland striped phenotype freq. = 0.43

$q_{2inland}$ = 0.43

$q_{coastal} = \sqrt{q_{2coastal}}$

= $\sqrt{0.22}$

= 0.4690

$q_{coastal}$= 0.47 i.e. 47%

$q_{inland} = \sqrt{0.43}$

= 0.655

$q_{inland}$ = 0.66 i.e. 66%

the migration range (m) is given as 20%

m= 0.2

allele freq. after migration = pre migration + ∆q

here,                  

∆q = change in the allele frequency

or                    

migration of allele freq. from coastal to inland

=$m(q_{coastal} - q_{inland})$

= 0.2 (0.47 – 0.66)  

=$0.2 \times (- 0.191)$

= - 0.0382    

∆q = -0.04   i.e. 4%