Answer:
No, the reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.
Step-by-step explanation:
Consider the provided information.
We need to determine that the reference point selected for the properties of a substance have any effect on thermodynamic analysis.
The answer for this question is No.
The reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.
Because in thermodynamic analysis we are deal with the change in the properties.
If we are doing calculation, the reference state chosen is irrelevant as long as we use values in a single consistent array of tables and charts.
Hence, The reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.
Answer:
-128x + 48 = -15
Step-by-step explanation:
I don't any choices to pick from but using the distributive property you will multiply the -4 by everything in the parenthesis.
-4(32x - 12) = -15
=-128x + 48 = -15.
Answer:

Step-by-step explanation:
Have in mind the definition of the term
, and now work on what the term
is based on the previous definition:

In the next step do NOT combine the numerical values, but try to identify the
term (
) in the expression (notice the use of square brackets to group the relevant terms):
![a_{n+1}=4\,n+4-1\\a_{n+1}=[4\,n-1]+4\\a_{n+1}=a_n+4](https://tex.z-dn.net/?f=a_%7Bn%2B1%7D%3D4%5C%2Cn%2B4-1%5C%5Ca_%7Bn%2B1%7D%3D%5B4%5C%2Cn-1%5D%2B4%5C%5Ca_%7Bn%2B1%7D%3Da_n%2B4)
So now we have the term "
" defined in a recursive manner based on the previous term "
"