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3 years ago

Find the m∠CDE, if m∠BAC = 50° and ∠BCA is a right angle. 40° 50° 90° 180°

Mathematics

2 answers:

serious [3.7K]3 years ago

6 0

< BAC = 50
< BCA = 90

interior angles of a triangle add up to 180

so < ABC = 180 - (90 + 50) = 180 - 140 = 40

and < ABC = < CDE.......so < CDE = 40 <===

atroni [7]3 years ago

6 0

The answer would be because if angle BAC= 50 degrees then angle DCE= 50 degrees. These triangles are the same. Each triangle has to equal 180 degrees. We know that this is a 90 degree triangle.
50, 90 is what we have so far and we need angle CDE. 50+90= 140
140+what=180
140+40=180 so the answer is
Angle CDE=40 degrees

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2 years ago

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mylen [45]

Step-by-step explanation:

ABC be the given isosceles right triangle such that <B = 90° , side AC is the hypotenuse; and, AB= BC

Then, (AB)^2 + (BC)^2 = (AC)^2…. Pythagoras theorem.

(AC)^2 = 98 sq. cm. ( given)

So, (AB)^2 + ((BC)^2 = 98

But, AB = BC = a ( say) …. ( given)

Therefore, a^2 + a^2 = 98

Or, 2a^2 = 98.

So, a^2 = 98 / 2 = 49

Hence, a = AB = BC = √49 = 7 cm.

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= 7 *√2 = 7* 1.414 = 9..898cm., say, 9.9 cm.

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<h2>please mark me as brainlist please </h2>

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The sum of three consecutive even integers is -78, what are the integers ?

Digiron [165]

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$ 
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Dmitriy789 [7]

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