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3 years ago

PLEASE HELP ME ANSWER THIS QUESTION

1 answer:

8 0

The equation of a circumference can be written as:
$(x - xh) {}^{2} + (y - yk) {}^{2} = r {}^{2}$
$(x - 5) {}^{2} + (y - 4) {}^{2} = 4$
$x {}^{2} - 10x + 25 + y {}^{2} - 8y + 16 - 4 = 0$
The solution is:
$x {}^{2} + y {}^{2} - 10x - 8y + 37 = 0$

You might be interested in

Factor completely 21x^3+35x^2+9x+15

Soloha48 [4]

Answer:

(3x+5)(7x^2+3)

Step-by-step explanation:

Factor : 21x^3+35x^2+9x+15

21x^3+35x^2+9x+15

=(3x+5)(7x^2+3)

______________________

Hope this helps!

7 0

2 years ago

What is (-8,10) and (5,-3) written in standard form?

Lady_Fox [76]

Answer:

x+y=2

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-3-10)/(5-(-8))

m=-13/(5+8)

m=-13/13

m=-1

y-y1=m(x-x1)

y-10=-1(x-(-8))

y-10=-(x+8)

y-10=-x-8

y=-x-8+10

y=-x+2

y-(-x)=2

y+x=2

x+y=2

4 0

3 years ago

If ΔOPQ is dilated from point Q by a scale factor of 3, which of the following equations is true about segment R prime S prime?

Sergio [31]

Answer:

$\overline {R'S'} = 3 {\overline {RS} }$

Step-by-step explanation:

The scale factor of dilation of triangle ΔOPQ, S.F. = 3

The center of dilation = Point <em>Q</em>

Therefore;

The length of the segment, ${\overline {S'Q'} }$ = 3 × The length of the segment, ${\overline {SQ} }$

Similarly;

The length of the segment, ${\overline {R'Q'} }$ = 3 × The length of the segment, ${\overline {RQ} }$

By Pythagoras theorem, we have;

${\overline {R'Q'} }^2 = {\overline {R'S'} }^2 + {\overline {S'Q'} }^2$

Therefore;

${\overline {R'S'} }^2 = {\overline {R'Q'} }^2 - {\overline {S'Q'} }^2 = \left ({3 \times \overline {RQ} } \right) ^2 - \left (3 \times {\overline {SQ} } \right) ^2 = 9 \times \left (\overline {RQ} } ^2 - {\overline {SQ} } ^2 \right) = 9 \times {\overline {RS} }^2$

$\therefore \sqrt{ {\overline {R'S'} }^2} = \sqrt{ 9 \times {\overline {RS} }^2}= 3 \times {\overline {RS} }$

$\overline {R'S'} = 3 \times {\overline {RS} }$ .

6 0

3 years ago

A girl throws a 2 kg rock with a net force of 6 N. What is the acceleration of the rock?

krek1111 [17]

Answer:
acceleration = 3 m/s²

Explanation:
From Newton's second law:
Force = mass * acceleration
We are given that:
Force = 6 Newton
mass = 2 kg

Substitute with the givens in the above equation to get the acceleration as follows:
Force = mass * acceleration
6 = 2 * acceleration
acceleration = 6 / 2 = 3 m/s²

Hope this helps :)

8 0

3 years ago

What is the value of x? How do you set up to solve?

nlexa [21]

Answer:

3x-22=80+x

3x-x=80+22

2x=102

x=51

Step-by-step explanation:

the exterior angle is (3x-22) and then is equal to sum of 80 and x

and then we get 51

6 0

2 years ago

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